The attached figure represents the box and whisker plots
<h3>How to create a box and whisker plot?</h3>To do this, we start by converting the tallies in the frequency table to numerical values.
So, we have:
Monday Tuesday Wednesday Thursday Friday
On Time 6 3 2 10 10
Late 1 0 3 4 10
Next, we enter these data on a graphing/statistical calculator to create the box and whisker plots
See attachment
Read more about box and whisker plot at:
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Answer:
a. The initial amount was 10 mg.
b. The percentage of the drug leaving the body each hour is 0.18, this is 18% per hour.
c. The amount of drug that remains in the body 6 hours after dosing is 3.04 mg.
d. The time until only 1 mg of the drug remains in the body is 11.6 hours.
Step-by-step explanation:
You know that at time t hours after taking the cough suppressant hydrocodone bitartrate, the amount, A, in mg, remaining in the body is given by :
a. The initial quantity occurs when time t is the initial t, that is, t is equal to 0. Then:
A=10
<u><em>The initial amount was 10 mg.</em></u>
b. Considering that an exponential growth is determined by:
, where A is the amount after a certain number of a certain time, Ao is the initial amount, r is the rate and t is the time, so the percentage of the drug that leaves the body each hour is :
1-r=0.82
Solving:
1-r -1= 0.82 -1
-r= -0.18
r= 0.18
<u><em>The percentage of the drug leaving the body each hour is 0.18, this is 18% per hour.</em></u>
c. The amount of drug that remains in the body 6 hours after dosing is when t = 6:
Solving:
A= 3.04 mg
<u><em>The amount of drug that remains in the body 6 hours after dosing is 3.04 mg.</em></u>
d. The time that passes until only 1 mg of the drug remains in the body is calculated taking into account that A = 1 mg:
Solving:
㏒ 0.1= t*㏒ 0.82
㏒ 0.1 ÷ ㏒ 0.82= t
11.6 hours= t
<u><em> The time until only 1 mg of the drug remains in the body is 11.6 hours.</em></u>
Answer:
1,539
Step-by-step explanation:
Using Simple Random Sampling in an infinite population (this is such a large population that we do not know the exact number) we have that the sample size should be the nearest integer to
where
<em>Z= the z-score corresponding to the confidence level, in this case 90%, so Z=1.645 (this means that the area under the Normal N(0,1) between [-1.645,1.645] is 90%=0.9) </em>
<em>p= the proportion of young urban people (ages 21 to 35 years) who go to at least 3 concerts a year= 35% = 0.35 </em>
<em>q = 1-p = 0.65 </em>
<em>e = the error proportion = 2% = 0.02 </em>
Making the calculations
So, the sample size should be 1,539 young urban people (ages 21 to 35 years)