The question might have some mistake since there are 2 multiplier of t. I found a similar question as follows:
The population P(t) of a culture of bacteria is given by P(t) = –1710t^2+ 92,000t + 10,000, where t is the time in hours since the culture was started. Determine the time at which the population is at a maximum. Round to the nearest hour.
Answer:
27 hours
Step-by-step explanation:
Equation of population P(t) = –1710t^2+ 92,000t + 10,000
Find the derivative of the function to find the critical value
dP/dt = -2(1710)t + 92000
= -3420t + 92000
Find the critical value by equating dP/dt = 0
-3420t + 92000 = 0
92000 = 3420t
t = 92000/3420 = 26.90
Check if it really have max value through 2nd derivative
d(dP)/dt^2 = -3420
2nd derivative is negative, hence it has maximum value
So, the time when it is maximum is 26.9 or 27 hours
There is no picture attached.
explanation:
We have the same workbook lol
The answer is
Drums: 2/4
milks 4/9
(unless your teacher wants it improper.)
Answer:
d. An additional month of buying and selling is associated with an additional $417 in profits.
Step-by-step explanation:
We have general form of intercept form of equation:
y = m*x + c ----- (A)
Given equation is : y = 2502 + 417*x
Rewrite equation: y = 417*x + 2502 ------(B)
comparing equation (B) with equation (A), we get
m = 417 (additional benefits per month) because multiplied factor x is the month.
Answer:
1 solution (x = 1.5)
Step-by-step explanation:
2x + 2 - 3x = 3x - 4
First, combine like terms
2 - x = 3x - 4
Add 4 to both sides
6 - x = 3x
Add x to both sides
6 = 4x
Divide both sides by 4
1.5 = x
