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Karo-lina-s [1.5K]
3 years ago
9

Who is good at math?

Mathematics
1 answer:
Naddik [55]3 years ago
6 0
My friends say I'm really good at math. I am currently 3 grades ahead in math and I have always gotten A's.
You might be interested in
What is the coefficient in this expression? <br> 2/5pq<br> A) p<br> B) 2/5<br> C)2<br> D)5
borishaifa [10]

Answer: 34+35

Step-by-step explanation: 35+33 bc that equals 69

3 0
2 years ago
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Please help me do this question
bija089 [108]

Answer:

I would say three person(s).

4 0
3 years ago
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The manufacturer of Pepsi claims that its 2-liter bottles contain, on average, no more than 250 calories. A sample of 20 2-liter
Stels [109]

Answer:

Yes, Sample information does indicate that a 2-liter bottle of Pepsi contains more than 250 calories  

Step-by-step explanation:  

Null Hypothesis [H0] : u < 250  

Alternate Hypothesis [H1] : u > 250 {One Tail}  

t = (x' - u) / [ sd / √n ]  

= (255 - 250) / (5.6 / √20)  

5 / (5.6 /√20)  

= 3.99  

As t ie 3.99 > t value 1.65 ie for one tail 95% confidence level. So, we reject the null hypothesis & conclude that it contains more than 250 calories.  

4 0
3 years ago
Solve 12^x^2+5x-4 = 12^2x+6
faust18 [17]

The solutions for ‘x’ are 2 and -5

<u>Step-by-step explanation:</u>

Given equation:

                    12^{x^{2}+5 x-4}=12^{2 x+6}

Since the base on both sides as ‘12’ are the same, we can write it as

                     x^{2}+5 x-4=2 x+6

                     x^{2}+5 x-2 x-4-6=0

                     x^{2}+3 x-10=0

Often, the value of x is easiest to solve by a x^{2}+b x+c=0 by factoring a square factor, setting each factor to zero, and then isolating each factor. Whereas sometimes the equation is too awkward or doesn't matter at all, or you just don't feel like factoring.

<u>The Quadratic Formula:</u> For a x^{2}+b x+c=0, the values of x which are the solutions of the equation are given by:

                       x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}

Where, a = 1, b = 3 and c = -10

                       x=\frac{-3 \pm \sqrt{(-3)^{2}-4(1)(-10)}}{2(1)}

                       x=\frac{-3 \pm \sqrt{9+40}}{2}

                       x=\frac{-3 \pm \sqrt{49}}{2}=\frac{-3 \pm 7}{2}

So, the solutions for ‘x’ are

                       x=\frac{-3+7}{2}=\frac{4}{2}=2

                       x=\frac{-3-7}{2}=\frac{-10}{2}=-5

The solutions for ‘x’ are 2 and -5

6 0
3 years ago
Read 2 more answers
Which algebraic expression is equivalent to the expression below?
prohojiy [21]
You can again ignore the parenthesis because you are not distributing anything. 
Your equation will look like this

3x + 11 + 6x

You can move each of these numbers around any way you like. You can combine the 3x and the 6x if you want, but they did not do that. You cannot take the x away and put it in front of the 11 though.

B. is your answer. All they did was move the 6x inside the parenthesis and the 11 out of the parenthesis. 

Always remember, when you are adding things together, the parenthesis don't matter! 
3 0
3 years ago
Read 2 more answers
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