The work done (in foot-pounds) in stretching the spring from its natural length to 0.7 feet beyond its natural length is 1.23 foot-pound
<h3>Data obtained from the question</h3>
From the question given above, the following data were obtained:
- Force (F) = 3 pounds
- Extension (e) = 0.6 feet
- Work done (Wd) =?
<h3>How to determine the spring constant</h3>
- Force (F) = 3 pounds
- Extension (e) = 0.6 feet
- Spring constant (K) =?
F = Ke
Divide both sides by e
K = F/ e
K = 3 / 0.6
K = 5 pound/foot
Thus, the spring constant of the spring is 5 pound/foot
<h3>How to determine the work done</h3>
- Spring constant (K) = 5 pound/foot
- Extention (e) = 0.7 feet
- Work done (Wd) =?
Wd = ½Ke²
Wd = ½ × 5 × 0.7²
Wd = 2.5 × 0.49
Wd = 1.23 foot-pound
Therefore, the work done in stretching the spring 0.7 feet is 1.23 foot-pound
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120 mL
Step-by-step explanation:
If the 480 mL has 75% concentration, then 360 mL are alcohol. To turn the 360 into only 60%, you need to increase the amount of water.
Dog weigh: 23
cat weigh: 5/8 dogs weigh
so..
23x5/8 = 115/8
Answer:
no diagram
Step-by-step explanation:
Answer:
Using the visual, 20 blocks, but you still need to change it to match the problem's scale
Step-by-step explanation:
First just try to find a way out and count the blocks. That's what I did. The part I haven't done is scale it. As the starting and end points of the grid are given, but where they fall is not clear, I don't know what the block to number ratio is. Sorry, maybe ask a teacher, they shouldn't take off any points.
