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Dvinal [7]
3 years ago
5

1. Charles and Cole measured the height of each of their dogs. The heights (at the

Mathematics
1 answer:
Ira Lisetskai [31]3 years ago
7 0

Answer:

C. 3.2

Step-by-step explanation:

Heights of dogs: 10, 22, 15, 12, 16

✔️Find the mean of the data set = \frac{10 + 22 + 15 + 12 + 16}{5} = \frac{75}{5} = 15

✔️Find |data value - mean|:

|10 - 15| = 5

|22 - 15| = 7

|15 - 15| = 0

|12 - 15| = 3

|16 - 15| = 1

✔️Find the sum of |data value - mean| and divide by 10:

\frac{5 + 7 + 0 + 3 + 1}{5} = \frac{16}{5} = 3.2

✅M.A.D = 3.2

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Answer:

Its 4

Step-by-step explanation:

You would have to do the formula for finding slope

y2-y1/x2-x1

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Can someone help me please? I don't nderstand this
musickatia [10]

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h^2=P^2+b^2

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A polynomial function has roots –5 and 1. Which of the following could represent this function?
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3 years ago
How many committees of 4 boys and 3 girls<br> can be formed from a class of 6 boys and 7<br> girls?
VLD [36.1K]

Answer:

525

Step-by-step explanation:

This is a question involving combinatorics

The number of ways of choosing a subset k from a set of n elements is given by {n \choose k} which evaluates to \frac{n!}{k!(n-k)!}

n! is the product n × (n-1) × (n-2) x....x 3 x 2 x 1

For example,

4! = 4 x 3 x 2 x 1 = 24

3! = 3 x 2 x 1 = 6

Since we have to choose 4 boys from a class of 6 boys, the total number of ways this can be done is

{6 \choose 4} = \frac{6!}{4!(6-4)!} = \frac{6!}{4!2!}

Note that 6! = 6 x 5 x 4 x 3 x 2 x 1 and 4 x 3 x 2 x 1  is nothing but 4!

So the numerator can be re-written as 6 x 5 x (4!)

We can rewrite the expression \frac{6!}{4!2!} \text{ as } \frac{6.5.4!}{4!2!}

Cancelling 4! from both numerator and denominator gives us the result

as  (6 × 5)/2! = 20/2 = 15 different ways of choosing 4 boys from a class of 6 boys

For the girls, the number of ways of choosing 3 girls from a class of 7 girls is given by

{7 \choose 3} = \frac{7!}{3!(7-3)!} = \frac{7!}{3!4!}

This works out to (7 x 6 x 5 )/(3 x 2 x 1)  (using the same logic as for the boys computation)

= 210/6 = 35

So total number of committees of 4 boys and 3 girls that can be formed from a class of 6 boys and 7 girls = 15 x 35 = 525

8 0
2 years ago
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