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3 years ago

8

Find the slope between the following points, show all work. (-1, -8) and (-3, -2)

1 answer:

Hatshy [7]3 years ago

5 0

How you get this answer is do delta y over delta x so that means take your y values (-8 and -2) and subtract and do the same thing with your x values so subtract (-1 and -3) so then youll end up with: -6 over 2, next steo is to see if you can simplify, and in this case you can so divide 2 and 6 so youll end up with -3 as your final answer. (this should be written in fraction form)

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3 years ago

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3 0

2 years ago

How do you turn 140 into a fraction

Nimfa-mama [501]

140/1

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5 0

3 years ago

Read 2 more answers

PLZZZZ HELP <br> A. 178.3<br> B. 196.5 <br> C. 250.8<br> D. 292.5<br> E. 297. 1

stepladder [879]

Answer:

E, 297.1

Step-by-step explanation:

First, find the area of the triangle using the formula a= (bh) / 2

Base x height would be 16 x 12, which is 192

192 / 2 is 96 sq meters

Then, find the area of the circle using the formula a= Pi (r^2)

If the diameter is 16, the radius would be 8 because you divide by 2

8^2 is 64, 64 times Pi is approximately 201.1

Finally, add the areas together, 96 + 201.1 is 297.1 or E

8 0

3 years ago

Find the length of the height of the right trapezoid shown below, if it has the greatest possible area and its perimeter is equa

Artyom0805 [142]

Answer:

The height of the right trapezoid is $\frac{6}{5+\sqrt{3}}\ units$

Step-by-step explanation:

Let

x ----> the height of the right trapezoid in units

we know that

The perimeter of the figure is equal to

$P=AB+BC+CD+DH+HA$

we have

$P=6\ units$

$AB=BC=CH=HA=x$ ---> because is a square

substitute

$6=x+x+CD+DH+x$

$6=3x+CD+DH$ -----> equation A

<em>In the right triangle CDH</em>

$sin(30\°)=\frac{CH}{CD}$

$sin(30\°)=\frac{1}{2}$

so

Remember that $CH=x$

$\frac{1}{2}=\frac{x}{CD}$

$CD=2x$

$tan(30\°)=\frac{CH}{DH}$

$tan(30\°)=\frac{\sqrt{3}}{3}$

so

$\frac{\sqrt{3}}{3}=\frac{x}{DH}$

$DH=x\sqrt{3}$

substitute the values in the equation A

$6=3x+CD+DH$ -----> equation A

$CD=2x$

$DH=x\sqrt{3}$

$6=3x+2x+x\sqrt{3}$

$6=5x+x\sqrt{3}$

$6=x[5+\sqrt{3}]$

$x=\frac{6}{5+\sqrt{3}}\ units$

5 0

2 years ago