PLEASE HELP ASAP! AND PLEASE DO NOT GIVE ME ANY VIRUSES!

Chemistry

1 answer:

loris [4]2 years ago

6 0

Answer:

In this situation

The limiting factors for spider has increased

As The flowers has increased the amount of the insects

And insects are the food of dpiders so spider made their homes there.

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What is the cell potential of an electrochemical cell that has the half-reactions shown below?

Karo-lina-s [1.5K]

Answer:

E°(Ag⁺/Fe°) = 0.836 volt

Explanation:

3Ag⁺ + 3e⁻ => Ag°; E° = +0.800 volt

Fe° => Fe⁺³ + 3e⁻ ; E° = -0.036 volt

_________________________________

Fe°(s) + 3Ag⁺(aq) => Fe⁺³(aq) + 3Ag°(s) ...

E°(Ag⁺/Fe°) = E°(Ag⁺) - E°(Fe°) = 0.800v - ( -0.036v) = 0.836 volt

4 0

2 years ago

Can some body plz help correct me or correct the true or false answers I did wrong. I’m not sure there right :(

3241004551 [841]

4 3 and 5 are wrong:)

4 is true and 5 is false

4. insulators are really thick materials that keep electrons within their space.

For example, a charger the rubber is the insulators and the electrons are flowing inside of the charger so you don't get shocked.

5. without the force of attraction, there are no atoms:)

for number 3, its a trick question

Hope this helped!

(learned these this year so I didn't forget them:)

8 0

2 years ago

Chlorine gas reacts with aluminum metal producing aluminum chloride. What mass of chlorine reacts with 9.00g of Al to form AlCl3

Anit [1.1K]

The mass of chlorine that react with 9.00 g of Al to form AlCl3 is 35.465 grams

Explanation
write the equation for reaction
that is
2 Al + 3 Cl2 = 2 Al CL3
find the moles of Al reacted

moles = mass/molar mass

9 g/ 27 g/mol = 0.333 moles of Al

by use of mole ratio between Al to Cl2 which is 2:3 find the moles of Cl2

mole of cl2 = 0.333 x3/2 = 0.4995 moles

mass of Cl2 is therefore = moles x molar mass

= 0.4995 x71 = 35.465 moles

6 0

3 years ago

The solubility of a gas is 0.890 g/L at a pressure of 120 kPa. What is the solubility of the gas if the pressure is changed to 1

IgorC [24]

The solubility of the gas if the pressure is changed to 100 kPa is 0.742 g/L

<h3>Effect of Pressure on Solubility </h3>

As the <em>pressure </em>of a gas increases, the <em>solubility </em>increases, and as the <em>pressure </em>of a gas decreases, the <em>solubility </em>decreases.

Thus, Solubility varies directly with Pressure

If S represents Solubility and P represents Pressure,

Then we can write that

S ∝ P

Introducing proportionality constant, k

S = kP

S/P = k

∴ We can write that

$\frac{S_{1} }{P_{1} } = \frac{S_{2} }{P_{2} }$