Mol of Kr gas = 1.244
<h3>Further explanation</h3>
In general, the gas equation can be written
<h3> PV=nRT
</h3>
where
P = pressure, atm
V = volume, liter
n = number of moles
R = gas constant = 0.08205 L.atm / mol K
T = temperature, Kelvin
P=1.31 atm
V=23.3 L
T=26+273=299 K
mol of sample :

The boiling point and distillation temperature of a substance are the same. The answer would be True
Answer:
decane
Explanation:
decane has 10 carbon and 22hydrogen