What is brass, salt, water an example of

Three objects have velocities that vary with time

Solnce55 [7]

#21

initial velocity=u=5m/s
Time=t=2s
Acceleration=a=1.3m/s²

According to first equation of kinematics

v=u+at
v=5+1.3(2)
v=5+2.6
v=7.6m/s

#22

#a

v1=2+3(3)=2+9=11m/s
v2=-8-4(3)=-20m/s
v3=1-5(3)=-14m/s

The order is

v2<V3<v1

#b

for speed find absolute velocity

S1=|11|=11m/s
S2=|-20|=20m/s
S3=|-14|=14m/s

So order is

S1<S3<S2

7 0

2 years ago

Read 2 more answers

What would BEST account for the lack of population in the southwestern portion of Africa?

Arada [10]

It has the highest birthrate and will triple its population by 2050. "There is a lack of appropriate infrastructure, health care, access to hospitals, education and jobs for these people," Kaps said, outlining the dilemma many African countries will face in the future. Despite waning infant mortality, the average birthrate of 4.7 children per woman remains high when compared with the rest of the world.

8 0

3 years ago

Any forensic scientist is equipped to study an explosion crime site.

arsen [322]

Answer:

false

Explanation:

I had the same answer for this question on my schoolwork

:) HOPE THIS HELPS

3 0

3 years ago

How does the height of a ramp affect the time it takes for an object to move down the ramp? please explain each one below:

weqwewe [10]

The greater the height of a ramp, the shorter the time it takes for an object to move down the ramp.

The greater the amount of salt, the In addition the larger the longer it takes water to boil.

An increase in volume of water increases the time it takes to boil and vice versa.

Increase in the length of the paper airplane, the farther it will fly.

Jumping Jack increases the heart rate.

<h3>How does the height of a ramp affect the time it takes for an object to move down the ramp?</h3>

A ramp is an inclined plane which is a form of simple machine that is used to lift heavy objects off the floor or to lower heavy objects down.

The greater the height of a ramp, the shorter the time it takes for an object to move down the ramp due to increased acceleration.

<h3>How does the amount of salt affect how long it takes water to boil?</h3>

The addition of solutes to pure solvent raises the boiling point of the solute.

Therefore, the greater the amount of salt, the In addition the larger the longer it takes water to boil.

<h3>How does the volume of water affect how long it will take to boil?</h3>

The mass of water increases with increase in volume of water.

Therefore, an increase in volume of water increases the time it takes to boil and vice versa.

<h3>How does the length of a paper airplane affect how far it will fly?</h3>

For a paper airplane the larger its wings, the greater the lift generated.

The greater the lift, the farther the paper airplane will fly.

Therefore, an increase in the length of the paper airplane, the farther it will fly.

<h3>How do jumping jacks affect your heart rate?</h3>

Exercise increases the heart rate.

Jumping jack is a for of exercise. Therefore, Jumping Jack increases the heart rate.

Learn more about ramp and inclined plane at: brainly.com/question/10352783

#SPJ1

7 0

1 year ago

Consider a wire of a circular cross-section with a radius of R = 3.17 mm. The magnitude of the current density is modeled as J =

Sloan [31]

Answer:

The current is $I = 8.9 *10^{-5} \ A$

Explanation:

From the question we are told that

The radius is $r = 3.17 \ mm = 3.17 *10^{-3} \ m$

The current density is $J = c\cdot r^2 = 9.00*10^{6} \ A/m^4 \cdot r^2$

The distance we are considering is $r = 0.5 R = 0.001585$

Generally current density is mathematically represented as

$J = \frac{I}{A }$

Where A is the cross-sectional area represented as

$A = \pi r^2$

=> $J = \frac{I}{\pi r^2 }$

=> $I = J * (\pi r^2 )$

Now the change in current per unit length is mathematically evaluated as

$dI = 2 J * \pi r dr$

Now to obtain the current (in A) through the inner section of the wire from the center to r = 0.5R we integrate dI from the 0 (center) to point 0.5R as follows

$I = 2\pi \int\limits^{0.5 R}_{0} {( 9.0*10^6A/m^4) * r^2 * r} \, dr$

$I = 2\pi * 9.0*10^{6} \int\limits^{0.001585}_{0} {r^3} \, dr$

$I = 2\pi *(9.0*10^{6}) [\frac{r^4}{4} ] | \left 0.001585} \atop 0}} \right.$

$I = 2\pi *(9.0*10^{6}) [ \frac{0.001585^4}{4} ]$

substituting values

$I = 2 * 3.142 * 9.00 *10^6 * [ \frac{0.001585^4}{4} ]$

$I = 8.9 *10^{-5} \ A$

5 0

4 years ago