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saw5 [17]
3 years ago
13

Me pueden ayudar es urgente es para mañana son el 25 y 34

Physics
1 answer:
RSB [31]3 years ago
7 0

Answer:

no se puede ver las palabras si la en cerraran asi l

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(Plzzzz help!!!) (50 points!!!)
stellarik [79]

Answer:

Write the following Quantitiesin scientific notation.

a. 10130 Pa to 2 decimal place

b. 978.15m * s-2 to one decimal place

c 0.000001256 A to3 decimal place​

Add your answer and earn points.

Answer

5.0/5

2

kobenhavn

Expert

5.5K answers

43M people helped

Answer: a.

b.  

c.  

Explanation:

Scientific notation is defined as the representation of expressing the numbers that are too big or too small and are represented in the decimal form with one digit before the decimal point times 10 raise to the power.

For example : 5000 is written as

a. 10130 Pa to 2 decimal place is written as

b.  to 1 decimal place is written as

c.   to 3 decimal places is written as

Explanation:

4 0
2 years ago
Read 2 more answers
When does a star reach equilibrium?
LenaWriter [7]
A protostar reaches equilibrium when gravity is balanced by the outward force of nuclear fusion. 
6 0
3 years ago
What lasts longer... a perm, or a chemical relaxer for your hair ?
Dmitrij [34]

Answer:

Perm lasts longer

Explanation:

Cuz a chemical relaxer only lasts a few weeks and a perm lasts a few months hope this helps

7 0
2 years ago
011 10.0 points
Sedbober [7]
<h2>The temperature of the air is 66.8° C</h2>

Explanation:

From the Newton's  velocity of sound relationship , the velocity of sound is directly proportional to the square root of temperature .

In this case The velocity of sound = frequency x wavelength

= 798 x 0.48 = 383 m/sec

Suppose the temperature at this time = T K

Thus 383 ∝ \sqrt{T}                       I

The velocity of sound is 329 m/s at 273 K ( given )

Thus 329 ∝ \sqrt{273}                   II

Dividing I by II , we have

\frac{383}{329} = \sqrt{\frac{T}{273} }

or \frac{T}{273} = 1.25

and T = 339.8 K  = 66.8° C

4 0
3 years ago
The electric potential in a region of space is \[V=350/\sqrt{x ^{2}+y ^{2}}\] where x and y are in meters. what is the strength
VARVARA [1.3K]
So the given value or the formula in getting the electric potential region of space is V=350/sqrt of x^2+y^2. So the given data is x and y is equals to 2.6 and 2.8. So in my calculation i came up with an answer of 91.6
8 0
3 years ago
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