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siniylev [52]
3 years ago
8

Right triangle abc and pqr are shown below what angle is congruent to angle a and b what is the area in squares of triangle pr4

Mathematics
1 answer:
Effectus [21]3 years ago
4 0
6x3=18-3=15 Hope it helps
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3/4(8x-4)=7x+2, I need to find out the answer
laiz [17]

Answer: x = -5

Step-by-step explanation:

First convert 3/4 to decimal= 0.75

0.75 (8x - 4) = 7x + 2

6x - 3 = 7x + 2

Transpose 7x from right hand side to the left hand side

6x - 7x = 2 + 3

-x = 5

x = -5

I hope this helps.

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3 years ago
I have a math question that im stuck on 2 - 2x ≥ x + 66
kakasveta [241]

Answer:

x is less than or equal to 64/-3

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Which ten thousand does 117,290 round to
Leni [432]

Answer:

120,000

Step-by-step explanation:

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3 years ago
HELP PLEASE!! I DONT UNDERSTAND!!!!!!!!!! THANKS SO MUCH
8090 [49]

Hello, please consider the following.

We will multiply the numerator and denominator by

4+\sqrt{6x}

to get rid of the root in the denominator.

First of all, we cannot divide by 0, right? So, we need to make sure that the denominator is different from 0.

4-\sqrt{6x} =0\sqrt{6x}=4\\\\\text{Take the square}\\\\6x=4^2=16\\\\x=\dfrac{16}{6}=\dfrac{8}{3}

We need to take any x real number different from 8/3 then and simplify the expression.

Let's do it!

\begin{aligned}\dfrac{4}{4-\sqrt{6x}}&=\dfrac{4(4+\sqrt{6x})}{(4+\sqrt{6x})(4-\sqrt{6x})}\\\\&=\dfrac{4(4+\sqrt{6x})}{(4^2-\sqrt{6x}^2)}\\\\&=\dfrac{4(4+\sqrt{6x})}{(16-6x)}\\\\&=\dfrac{2(4+\sqrt{6x})}{(8-3x)}\\\\&\large \boxed{=\dfrac{8+2\sqrt{6x}}{8-3x}}\end{aligned}

Thank you

8 0
3 years ago
Point M is the midpoint of segment AB. If AM = 50 – 3x and MB = –20 + 4x, find the value of AM
love history [14]
The answer to your question is 20
4 0
3 years ago
Read 2 more answers
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