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densk [106]
3 years ago
9

A deep sea diving bell is being lowered at a constant rate. After 10 ​minutes, the bell is at a depth of 600 ft. After 40 minute

s the bell is at a depth of 1 comma 700 ft. What is the average rate of lowering per​ minute? Round to the nearest hundredth.
Mathematics
1 answer:
Degger [83]3 years ago
7 0
<h2>Average rate of lowering per​ minute = 36.67 ft/min</h2>

Step-by-step explanation:

After 10 ​minutes, the bell is at a depth of 600 ft

After 10 minutes

                   Depth of bell = 600 ft

After 40 minutes the bell is at a depth of 1,700 ft.

After 40 minutes

                   Depth of bell = 1700 ft

Time gap = 40 - 10 = 30 minutes

Depth fallen = 1700 - 600 = 1100 ft

We have

           Depth fallen = Average rate of lowering per​ minute x Time gap

           1100 = Average rate of lowering per​ minute x 30

           Average rate of lowering per​ minute = 36.67 ft/min

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Answer: Sammy


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Hope this helps!


5 0
3 years ago
The diagram below shows 5 identical bowls stacked one inside the other. The height of 1 bowl is 2 inches. The height of 5 bowls
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(Bowls, Height) (1, 2)  (5,5)

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B=1.25.  Y= 0.75*x + 1.25. 

Part B
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7 0
2 years ago
If 6 pounds of apples cost $4.80 what is the cost per 9 pounds
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6 0
2 years ago
Read 2 more answers
Consider that an = 4n-1 represents a sequence. What is the tenth term? A) 361 B) 512 C) 1,024 D) 4,096 E) 262,144
mel-nik [20]

Hello from MrBillDoesMath!

Answer:

Choice E.

Discussion:

Assuming that n >=1, a(n) = 4n -1, then

a(10) = 4(10) - 1 = 39    

but that doesn't match any of the answers...... hmm...

BUT

If you meant that a(n) = 4^(n-1),  then

a(10) = 4^(10-1) = 4^9 =  262144    

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4 0
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cupoosta [38]

0  Pretend that is theta XD


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cot 0 = \frac{2}{\sqrt{5}} (\frac{\sqrt{5} }{\sqrt{5} })

cot 0 = \frac{2\sqrt{5}}{5}


5 0
3 years ago
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