Answer: 39.13
Step-by-step explanation:
:)
To answer this question, you should set up and equation before doing anything else. So for this question you 're going to set up two equations.
The first equation is 2x+5y=33
The second equation is 8x+3y=30
Once you do that you have to solve for either X or Y by canceling out the other one. In this problem figuring out the Y is easier because you can cancel the X's more easily than the Y. To cancel a variable, they have to add up to 0.
So to cancel the X you multiply the equation 2x+5y=33 by -4.
That gives you -8x-20y= -132
Then you set up the two equations and add them together.
(-8x-20y= -132) + (8x+3y=30)
That gives you -17y = -102
So then you solve for Y by dividing by -17. You find out that Y is equal to 6. Then you plug the 6 back into the ORIGINAL equations and solve for X, which turns out to be 1.5
Hope this helped and if you get confused or have questions please ask :)
[ ( x + 4 )( x + 5 ) + 4( x + 1 )( x + 5) - 5( x + 1 )( x + 4 ) ] / [( x + 1 )( x + 4)( x + 5 )] = ( x^2 + 9x + 20 + 4x^2 + 24x +20 - 5x^2 - 25x - 20) / [( x + 1 )( x + 4)( x + 5 )] =
( - 2x + 20 ) / [( x + 1 )( x + 4)( x + 5 )] = ( - 2)( x - 10) / [( x + 1 )( x + 4)( x + 5 )]
What do u need help with what the math problem??!?
I am willing to help if I can
The greatest area he can fence is 64 ft².
In order to maximize area and minimize perimeter, we use dimensions that are as close to equivalent as possible. 32 feet of fence for 4 sides gives us 8 feet of fence per side. We would have a square whose side length is 8; the area would be 8*8 = 64.
