Number 1 is:
C and E
Number 2 is:
400
The value of P(4, 6) when the two number cubes are tossed is 1/36
<h3>How to determine the probability?</h3>
On each number cube, we have:
Sample space = {1, 2, 3, 4, 5, 6}
The individual probabilities are then represented as:
P(4) =1/6
P(6) =1/6
The value of P(4, 6) when the two number cubes are tossed is:
P(4, 6) = P(4) * P(6)
This gives
P(4, 6) = 1/6 * 1/6
Evaluate
P(4, 6) = 1/36
Hence, the value of P(4, 6) when the two number cubes are tossed is 1/36
Read more about probability at:
brainly.com/question/24756209
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Answer:
switched signs around
Step-by-step explanation:
I believe that s/he switched the signs around so
|x|>5 is solved by x<-5 and x>5
but I'm not quite sure, sorry
Set this up as a proportion.
400/15 = x/6
Solve for x.
I just hope to help! :)
