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White raven [17]
3 years ago
12

Please help me with correct answer!!!

Mathematics
1 answer:
Free_Kalibri [48]3 years ago
3 0
There are 7 nickels and 8 dimes, if you look closely at the procedure, you can see how <em>x </em>is established for the nickels (0.05) and <em>y </em>for the dimes (0.10). 
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Find the slope of a line that goes through point A(8,-4) and C(2, -1)
Black_prince [1.1K]
The answer for finding the slope is -1/2
5 0
2 years ago
5x + 7y = 25<br> 5x - 2y = -65<br> solve using elimination<br> (step by step please)
aliina [53]

5x+7y=25

5x-2y=-65

subtract both of the equations

5x-5x=0

7y--2y= 7y+2y=9y

25--65=25+65=90

0+9y=90

9y=90

divide both sides by 9 to get y by itself

9y/9=90/9

cross out 9 and 9 which becomes 1*1*y=y

90/9=10

y=10

find x by using the substitution method

5x+7y=25

5x+7(10)=25

5x+70=25

move +70 to the other side

sign changes from +70 to -70

5x+70-70=25-70

5x=-45

divide both sides by 5 to get x by itself

5x/5=-45/5

cross out 5 and 5 then becomes 1*1*x=x

-45/5=-9

x=-9

answer:

(-9,10)

6 0
3 years ago
What is the slope of the line that passes through the pair of points (1/3, -1) and ( -2, 9/2)​
UkoKoshka [18]

Answer:

\boxed{m = - \frac{33}{14} }

.

Step-by-step explanation:

Use the form below

\boxed{\boxed{m = \frac{y_2 - y_1}{x_2 - x_1} }}

Where

  • m is a slope
  • (x_1,~y_1) and (x_2,~y_2) are the point of the line

.

So, the slope is

(\frac{1}{3} ,~ -1) \to x_1 = \frac{1}{3} ~and~y_1 = -1

(-2,~ \frac{9}{2} ) \to x_2 = -2~and~y_2 = \frac{9}{2}

.

m = \frac{\frac{9}{2} -(-1)}{-2-\frac{1}{3} }

m = \frac{\frac{11}{2} }{\frac{-7}{3} }

m = \frac{11}{2} \div (-\frac{7}{3} )

m = \frac{11}{2} \times (-\frac{3}{7} )

m = - \frac{33}{14}

.

Happy to help:)

7 0
3 years ago
Read 2 more answers
Given f (x) = 4x - 3,g(2) = x3 + 2x<br> Find (f - g) (4)
Ira Lisetskai [31]
Sgjklhcvffhxjjfjdjdjdhdhjfjd
5 0
2 years ago
X^6+3x^3-5 <br> write the expression in quadratic form
Art [367]

Step-by-step explanation:

v =  {x}^{3}  \\  {v}^{2}  + 3v - 5 = 0 \\

Solving this equation using the quadratic formula, we get two real solutions :

1.1926 or -4.1926

Now we know the values of v , we can calculate x since x is ∛ v

{x}^{6}  + 3 {x}^{3}  - 5 = 0

x =  \sqrt[3]{1.1926}  = 1.0605 \\ x =  \sqrt[3]{ - 4.1926}  =  - 1.6125

3 0
2 years ago
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