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3 years ago

How do you find the area of the field in terms of x

Mathematics

1 answer:

Alex_Xolod [135]3 years ago

4 0

Hello from MrBillDoesMath!

Answer: 104x^2 + 166x + 66

Discussion:

The area of a rectangle is given by "length" * "width". For us the formula becomes

(13x + 11) * (8x+6)

13x (8x +6) + 11 * (8x + 6) =

(13x * 8x + 13x* 6) + ( 11*8x + 11*6) =

(104x^2 + 78x ) + (88x + 66) =

104x^2 + (78x + 88x) + 66 =

104x^2 + 166x + 66

Thank you,

MrB

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What is the answer pls for this is hard who knows tell me

masha68 [24]

119.6

72/sin(37)= 119.6

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3 years ago

Karissa rides her bicycle for 4 hours and is 22 miles from her house. After riding for 8 hours, she is

inysia [295]

Answer:

5.5

Step-by-step explanation:

We nned to divide to solve this!!

22/4 = 5.5

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Have an amazing day!!

Please rate and mark brainliest!!!!

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2 years ago

I need help please please!!!

wel

Answer:

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Step-by-step explanation:

y = 5² + 10(5) + 16

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4 0

3 years ago

What is the 6th term of the geometric sequence where a1 = -4096 and a4 = 64?

Akimi4 [234]

$\bf \begin{array}{llccll}
term&value\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
a_1&-4096\\
a_2&-4096r\\
a_3&-4096rr\\
a_4&-4096rrr\\
&-4096r^3\\
&64
\end{array}\implies -4096r^3=64
\\\\\\
r^3=\cfrac{64}{-4096}\implies r^3=-\cfrac{1}{64}\implies r=\sqrt[3]{-\cfrac{1}{64}}
\\\\\\
r=\cfrac{\sqrt[3]{-1}}{\sqrt[3]{64}}\implies \boxed{r=\cfrac{-1}{4}}\\\\
-------------------------------$

$\bf n^{th}\textit{ term of a geometric sequence}\\\\
a_n=a_1\cdot r^{n-1}\qquad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
r=\textit{common ratio}\\
----------\\
r=-\frac{1}{4}\\
a_1=-4096\\
n=6
\end{cases}
\\\\\\
a_6=-4096\left( -\frac{1}{4} \right)^{6-1}\implies a_6=-4^6\left( -\frac{1}{4} \right)^5$

4 0

3 years ago

Read 2 more answers

An airplane ascended into the sky to a steady altitude of 35000 feet. The same plane descended to a steady altitude of 32000 fee

love history [14]

Answer:

3000 feets

Step-by-step explanation:

Given that :

Initial Ascent to steady altitude = 35,000 feets

Descent to steady altitude = 32,000 feets

Number of feets the plane descend :

(Initial ascent to steady altitude - descent to steady altitude)

(35000 - 32000) feets = 3,000 feets

6 0

3 years ago