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lana [24]
3 years ago
15

Points A and B have opposite x-coordinates but the same y-coordinates. How many units away are each of the points from the y-axi

s?
Mathematics
2 answers:
Maurinko [17]3 years ago
4 0

Answer:

They are both x units away from the y-axis.

Step-by-step explanation:

The x coordinates are x and -x  so they are both x units away from the y-axis. The total distance between the 2 points is  x -(-x) = 2x units.

Rufina [12.5K]3 years ago
3 0

Answer:

x units

Step-by-step explanation:

The points can be represented as:

(x,y) and (-x,y)

the distance from the first point to the y- axis is x, which can be any number.

and the distance from the second point, since is also at coordinate x but in the other side of the plane is also

For example: points (3,0) and (-3,0) they have the same y-coordinate 0.

And the x-coordinates are opposite (3 and -3).

and if you place these points in a plane, you can see that both are at the same distance from the y-axis (3 units).

So for any two points with this characteristics, both will be at a distance x from the y-axis.

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Answer:

-\frac{5}{4x}

Step-by-step explanation:

<h2>\left(-5x^3\right)^3\div \left(10x^5\right)^2</h2><h2>\frac{-5^3x^9}{\left(10x^5\right)^2}</h2><h2>\frac{-5^3x^9}{10^2x^{10}}</h2><h2>\frac{-5^3x^9}{5^2\cdot \:2^2x^{10}}</h2><h2>\frac{-5x^9}{2^2x^{10}}</h2><h2>\frac{-5}{2^2x}</h2>

-\frac{5}{4x}

- hope it helps! -

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3 0
2 years ago
Your sister is considering two different shapes for her garden. One is a square with side lengths of 3.5 meter, and the other is
Bess [88]
Hello! I can help you with this!

A. Okay. So, to find the area of the square all you have to do is the number square, or multiply the number by itself, in this case. 3.5. 3.5^2 is 12.25. The area of the square is 12.25 square meters large.

B. To find the area of the circle, you do pi*r^2. Radius is half the the diameter. Half of 4 is 2. 2^2 is 4. To multiply by pi, we can just do it as 3.14. 4 * 3.14 is 12.56. The circle is 12.56 square meters large.

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3 0
3 years ago
Please help me out............................
Alina [70]

Answer:

<h2>b = 15°</h2>

Step-by-step explanation:

If Pq = RQ then ΔPQR is the isosceles triangle. The angles QPR and PRQ have the same measures.

We know: The sum of the measures of the angeles in the triangle is equal 180°. Therefore we have the equation:

m∠QPR + m∠PRQ + m∠RQP = 180°

We have

m∠QPR = m∠PRQ and m∠RQP = 60°

Therefore

2(m∠QPR) + 60° = 180°       <em>subtract 60° from both sides</em>

2(m∠QPR) = 120°           <em>divide both sides by 2</em>

m∠QPR = 60° and m∠PRQ = 60°

Therefore ΔPRQ is equaliteral.

ΔPSR is isosceles. Therefore ∠SPR and ∠PRS are congruent. Therefore

m∠SPR = m∠PRS

In ΔAPS we have:

m∠SPR + m∠PRS + m∠RSP = 180°

2(m∠SPR) + 90° = 180°            <em>subtract 90° from both sides</em>

2(m∠SPR) = 90°             <em>divide both sides by 2</em>

m∠SPR = 45° and m∠PRS = 45°

m∠PRQ = m∠PRS + b

Susbtitute:

60° = 45° + b           <em>subtract 45° from both sides</em>

15° = b

3 0
3 years ago
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