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Trava [24]
3 years ago
9

Very good electrical conductivity

Chemistry
1 answer:
bonufazy [111]3 years ago
7 0
Huh? I need more info to answer this
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A 500. mL gas sample is collected over water at a pressure of 740 mmHg and 25.0 °C. What is the volume of the dry gas at STP?
Lera25 [3.4K]

Answer:

Volume of dry gas at STP = 0.432 liters or 432 ml

Explanation:

Given:

Pressure (P) = 740 mmHg - 24 mmHg = 716 mmHg

Temperature (t) = 25 degrees C + 273 K = 298 K

500 ml = 0.5 l

Find:

Volume of dry gas at STP

Computation:

[P1][V1] / T1 = [P2][V2] / T2

[716][0.5] / 298 K = [760][ x Liters] / 273 K

x = 0.432 Liters

Volume of dry gas at STP = 0.432 liters or 432 ml

7 0
3 years ago
A 2.20 mol sample of NO 2 ( g ) is added to a 3.50 L vessel and heated to 500 K. N 2 O 4 ( g ) − ⇀ ↽ − 2 NO 2 ( g ) K c = 0.513
igor_vitrenko [27]

Answer:

[NO₂] = 0.434 M

[N₂O₄] = 0.0971 M

Explanation:

The equilibrum is:  N₂O₄(g)  ⇆  2NO₂ (g)

1 moles of nitrogen (IV) oxide is in equilibrium with 2 moles of nitrogen dioxide.

Initally we only have 2.20 moles of NO₂. So let's write the equilibrium again:

              2NO₂ (g)   ⇆   N₂O₄(g)      

Initially   2.20 mol              -

React          x                      x/2

X amount has reacted, and the half has been formed, according to stoichiometry.

Eq       (2.20-x) / 3.50L     (x/2)/ 3.50L

We divide by the volume because we need molar concentrations. Let's make the Kc's expression:

Kc = [N₂O₄] / [NO₂]²

0.513 = ((x/2)/ 3.50L) /  [(2.20-x) / 3.50L]

0.513 = ((x/2)/ 3.50L) / [(2.20-x)² / 3.50L²]

0.513 = ((x/2)/ 3.50L) / [2.20-x)² / 3.50L²]

0.513 = ((x/2)/ 3.50L) / (4.84 - 4.40x + x²) / 12.25)

0.513 / 12.25 (4.84 - 4.40x + x²) = x/2 / 3.50

0.203 - 0.184x + 0.0419x² = x/2 / 3.50

3.50(0.203 - 0.184x + 0.0419x²) = x/2

7 (0.203 - 0.184x + 0.0419x²) - x = 0

1.421 - 2.288x + 0.2933x² = 0  → Quadratic formula

a = 0.2933 ;  b = -2.288 ; c = 1.421

(-b +- √(b²-4ac)) / (2a)

x₁ = 7.12

x₂ = 0.68 → We consider this value, so we can have a (+) concentration.

Concentrations in the equilibrium are:

[NO₂] = (2.20-0.68) / 3.50 = 0.434 M

[N₂O₄] = (0.68/2) / 3.50  = 0.0971 M

8 0
2 years ago
Endothermic or exothermic
yanalaym [24]

Answer:

endo takes energy in and exo releases it out

Explanation:

3 0
2 years ago
Which of the following statements concerning the measured number 0.3030
Dennis_Churaev [7]

Answer:

C

Explanation:

If you move the decimal to the left it transforms the expression into scientific notation.

8 0
3 years ago
The mass of an element is 27 and it's atomic number is 13. Give the composition of the nucleus of it's atom.
love history [14]

Answer:

nucleus consists of:

13 protons, 14 neutrons

8 0
2 years ago
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