Answer:
civic cgvvbbbibbbnn bnnnn
Explanation:
Usually most cells that carry anaerobic respiration utilize the Glycolysis pathway because it does not require oxygen. It is also believed it is the ancient metabolic pathway by utilized by primordial cells when the earth's atmosphere was not mainly oxygen,
Glycolysis consumes 2 ATPs (during the conversion of Glucose to Fructose 1,6 bisphosphate ) but produces a gross $ ATPs. It, therefore, has a net ATP of 2. This is inefficient when compared to the Krebs cycle that utilizes oxygen to produce 34 ATPs. Anaerobic respiration produces pyruvate. This pyruvate is broken down into an organic acid like lactic acid which is excreted from the cell, which is why fermented food tastes sour.
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Answer:
48.75 g of AgCl
11.60 g of H₂S
Solution:
The Balance Chemical Equation is as follow,
Ag₂S + HCl → AgCl + H₂S
<u>Calculate amount of AgCl produced</u><u>,</u>
According to equation,
247.8 g (1 mol) of Ag₂S produces = 143.32 g (1 mol) of AgCl
So,
84.3 g of Ag₂S will produce = X g of AgCl
Solving for X,
X = (84.3 g × 143.32 g) ÷ 247.8 g
X = 48.75 g of AgCl
<u>Calculate amount of H</u><u>₂</u><u>S produced</u><u>,</u>
According to equation,
247.8 g (1 mol) of Ag₂S produces = 34.1 g (1 mol) of H₂S
So,
84.3 g of Ag₂S will produce = X g of H₂S
Solving for X,
X = (84.3 g × 34.1 g) ÷ 247.8 g
X = 11.60 g of H₂S
Answer:
Explanation:
<u>1. Number of moles of gasoline</u>
a) Convert 60.0 liters to grams
- mass = 0.77kg/liter × 60.0 liter = 46.2 kg
- 46.2kg × 1,000g/kg = 46,200g
b) Convert 46,200 grams to moles
- molar mass of C₈H₁₈ = 114.2 g/mol
- number of moles = mass in grams / molar mass
- number of moles = 46,200g / (114.2 gmol) = 404.55 mol
<u>2. Number of moles of carbon dioxide, CO₂ produced</u>
a) Balanced chemical equation (given):
- C₈H₁₈ (l) + ²⁵/₂ O₂ (g) → 8 CO₂ (g) + 9 H₂O (g)
b) mole ratio:
- 1 mol C₈H₁₈ / 8 mol CO₂ = 404.55 mol C₈H₁₈ / x
Solve for x:
- x = 404.55mol C₈H₁₈ × 8 mol CO₂ / 1mol C₈H₁₈ = 3,236.4 mol CO₂
<u> 3. Convert the number of moles of carbon dioxide to volume</u>
Use the ideal gas equation:
- R = 0.08206 (mol . liter)/ (K . mol)
Substitute and compute:
- V =3,236.4 mol × 0.08206 (mol . liter) / (K . mol) 298.15K / 1 atm
Round to two significant figures (because the density has two significant figures): 79,000 liters ← answer
