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3 years ago

In Rutherfords gold foil experiment, what caused the deflection of the positively charged particles?

2 answers:

Alex3 years ago

5 0

Explanation: Rutherford took a gold foil and passed a beam of alpha-particles (carrying positive charge) through it and then he recorded some observations.

He thought that the alpha-particles will pass straight through the foil but to his surprise, some of the particles deflected their path and few of them deflected backward.

He concluded that the atom must have something which is carrying the same charge as that of the alpha particles which made them deflected back.

He finally concluded that the atom consists of tiny, dense and positively charged centre which he later called as nucleus.

dmitriy555 [2]3 years ago

3 0

The particles that completely went through passed through the empty space in the atom. The particlesthat were deflected to the sides were deflated by a passing electron that moved the alpha particle out of the way. The particles that were bounced back hit the nucleus in the center that it bounced off.


hoped that helped

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Which contains the greatest mass of oxygen: 0.75 mol of ethanol (C2H5OH), 0.60 mol of formic acid (HCO2H), or 1.0 mol of water (

alisha [4.7K]

Answer: formic acid (HCOOH) contains the greatest mass of oxygen

Explanation:Please see attachment for explanation

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4 years ago

The half-life of bismuth-210, 210bi, is 5 days. (a) if a sample has a mass of 184 mg, find the amount remaining after 15 days.

ASHA 777 [7]

Answer:- 23.0 mg

Solution:- Radioactive decay obeys first order kinetics and the first order kinetics equation is:

$lnN=-kt+lnN_0$

where, $N_0$ is the initial amount of radioactive substance and N is it's amount after time t. k is the decay constant.

From given information, Original amount, $N_0$ of the radioactive substance is 184 mg and we are asked to calculate the amount N after 15 days. It means, t = 15 days

Half life is given as 5 days. From the half life, we could calculate the decay constant k using the equation:

$k=\frac{0.693}{t_1_/_2}$

where, $t_1_/_2$ is the symbol for half life. let's plug in the value of half like to calculate k:

$k=\frac{0.693}{5days}$

$k=0.1386day^-^1$

Let's plug in the values in the first order kinetics equation and solve it for N:

$lnN=-0.1386day^-^1(15days)+ln184mg$

$lnN=-2.079+5.215$

lnN = 3.136

$N=e^3^.^1^3^6$

N = 23.0 mg

So, 23.0 mg of Bi-210 would be remaining after 15 days.

3 0

4 years ago

Explain why aluminum does not react with potassium nitrate (KNO3) although it reacts with copper nitrate.

Kipish [7]

Answer:

Potassium nitrate react with aluminum to produce potassium aluminate, aluminum oxide and nitrogen. This reaction takes place at a temperature near 400°C.

Explanation:

6KNO3 + 10Al → 6KAlO2 + 2Al2O3 + 3N2

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3 years ago

A compound has the name iodine pentafluoride. What kind of bond is present between the atoms? A. O Metallic B Covalent C. Hydrog

8090 [49]

Answer:

IF(subscript 5)

Explanation:

covalent.

3 0

3 years ago

Please help me answer this

Olenka [21]

I think is the Third one tbh sorry if that’s not right

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3 years ago