All categories

2 years ago

Can someone explain how to do this

Mathematics

2 answers:

sdas [7]2 years ago

5 0

You begin by finding the measure of the angles knowing that all angles in a triangle equal 180. Then you use tan 57=7/(line AC). This value squared plus 7 squared will equal the length of the hypotenuse squared.

Cloud [144]2 years ago

4 0

I'm pretty sure its a^2+b^2=C^2

You might be interested in

Which of the following statements is false

Molodets [167]

Answer:

the second one is false

3 0

2 years ago

Read 2 more answers

Triangle PQR is transformed to triangle P'Q'R'. Triangle PQR has vertices P(4, 0), Q(0, −4), and R(−8, −4). Triangle P'Q'R' has

Whitepunk [10]

Answer:

Please find attached the required plot accomplished with an online tool

Part A:

1/4

Part B:

P''(-1, 0), Q''(0, -1), and R''(2, -1)

Part C:

Triangle PQR is similar to triangle P''Q''R'' but they are not congruent

Step-by-step explanation:

Part A:

Triangle ΔPQR has vertices P(4, 0), Q(0, -4), R(-8, -4)

Triangle ΔP'Q'R' has vertices P'(1, 0), Q'(0, -1), R'(-2, -1)

The dimensions of the sides of the triangle are given by the relation;

$l = \sqrt{\left (y_{2}-y_{1} \right )^{2}+\left (x_{2}-x_{1} \right )^{2}}$

Where;

(x₁, y₁) and (x₂, y₂) are the coordinates on the ends of the segment

For segment PQ, we place (x₁, y₁) = (4, 0) and (x₂, y₂) = (0, -4);

By substitution into the length equation, we get;

The length of segment PQ = 4·√2

The length of segment PR = 4·√10

The length of segment RQ = 8

The length of segment P'Q' = √2

The length of segment P'R' = √10

The length of segment R'Q' = 2

Therefore, the scale factor of the dilation of ΔPQR to ΔP'Q'R' is 1/4

Part B:

Reflection of (x, y) across the y-axis gives;

(x, y) image after reflection across the y-axis = (-x, y)

The coordinates after reflection of P'(1, 0), Q'(0, -1), R'(-2, -1) across the y-axis is given as follows;

P'(1, 0) image after reflection across the y-axis = P''(-1, 0)

Q'(0, -1) image after reflection across the y-axis = Q''(0, -1)

R'(-2, -1) image after reflection across the y-axis = R''(2, -1)

Part C:

Triangle PQR is similar to triangle P''Q''R'' but they are not congruent as the dimensions of the sides of triangle PQR and P''Q''R'' are not the same.

6 0

3 years ago

Grade geo<br> Practice 7.3

TiliK225 [7]

Answer:

Nice to hear that, congrats with practice 7.3

4 0

2 years ago

Read 2 more answers

Which is the graph of f(x) = -3√x?<br>pls answer quickly

k0ka [10]

Answer: the graph farthest to the right is almost correct. If you substitute values for x in the function f(x)= -3√x , the output does not match the curve on the graphs shown.

If you have a choice that includes only a curve to the right of the y- axis, that would be better.

Step-by-step explanation: Square roots of Negative x-values will result in imaginary numbers. Otherwise the graph with the curve passing through coordinates (1,-3) (4,-6) and (9,-9) is a good choice.

(And ask your teacher about the square root of negative numbers on this graph.)

4 0

2 years ago

A rocket is launched from a tower. The height of the rocket , y in feet, is related to the time after launch, x in seconds, by t

Nikolay [14]

<h3>Answer: Max height = 455.6 feet</h3>

========================================================

Explanation:

The general equation

y = ax^2 + bx + c

has the vertex (h,k) such that

h = -b/(2a)

In this case, a = -16 and b = 147. This means,

h = -b/(2a)

h = -147/(2*(-16))

h = 4.59375

The x coordinate of the vertex is x = 4.59375

Plug this into the original equation to find the y coordinate of the vertex.

y = -16x^2+147x+118

y = -16(4.59375)^2+147(4.59375)+118

y = 455.640625

The vertex is located at (h,k) = (4.59375, 455.640625)

The max height of the rocket occurs at the vertex point. Therefore, the max height is y = 455.640625 feet which rounds to y = 455.6 feet

5 0

2 years ago