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3 years ago

Translate the word phrase into a variable expression.

Mathematics

1 answer:

Evgen [1.6K]3 years ago

6 0

B quotient means divide so it is x/3 then 8 less means to subtract

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Find the volume <br> thank you for the help

Sergeeva-Olga [200]

Answer:

all you need to do is multiply length times width times height.

Step-by-step explanation:

5 1/2 x 3= 16.5

16.5 x 2 1/4= 453.75

now just add both answers :)

I really hope this helps! <3 Good luck!

3 0

3 years ago

Shane found gift bags in packs of 8 and bows in packs of 10. If Shane wanted to have the

Sergeeva-Olga [200]

Answer:

5 gift bags

Step-by-step explanation:

8 x 5 = 40

10 x 4 = 40

4 0

3 years ago

In 1980, the number of high school dropouts in a country was 5217 thousand. By 2008, this number had decreased to 3120 thousand.

Veseljchak [2.6K]

Answer:

74893 students per year

Step-by-step explanation:

The Average rate of change is calculated as

= Difference in number of students / Difference in years

= 3120 thousand - 5217 thousands/ 2008 - 1980

= (3120000 - 5217000)/(2008 - 1980)

= -2097000/28

= -74892.857143 per year

Therefore, the average rate of change

per year in the number of high school dropouts is approximately 74893 students per year

8 0

4 years ago

Which expression is equivalent to 18s+9t+36

tatuchka [14]

18(s+t/2+2)

8 0

3 years ago

Mark the statement either true (in all cases) or false (for at least one example). If false, construct a specific example to sho

LUCKY_DIMON [66]

Answer with Step-by-step explanation:

We are given that $v_1,v_2,..,v_4$ are in $R^4$ and $v_1,v_2,v_3$ is linearly dependent then {v_1,v_2,v_3,v_4}[/tex] is also linearly dependent.

We have to find that given statement is true or false.

Dependent vectors:Dependent vectors are those vectors in which atleast one vector is a linear combination of other given vectors.

Or If we have vectors $x_1,x_2,....x_n$

Then their linear combination

$a_1x_1+a_2x_2+.....+a_nx_n=0$

There exist at least one scalar which is not zero.

If $v_1,v_2,v_3$ are dependent vectors then

$a_1v_1+a_2v_2+a_3v_3=0$ for scalars $a_1,a_2,a_3$

Then , by definition of dependent vectors

There exist a vector which is not equal to zero

If vector $v_3$ is a linear combination of $v_1\;and \;v_2$ , So at least one of vectors in the set is a linear combination of others and the set is linearly dependent.

Hence, by definition of dependent vectors

{ $v_1,v_2,v_3,v_4$ } is linearly dependent.

Option B is true.

8 0

3 years ago