You know that 3×9=27. explain how you know what 9×3 equals.

2 answers:

6 0

I know what 9x3 equals because if you simplify the equation it’s 9+9+9. You just add one number as many times as the other number.

Zinaida [17]3 years ago

5 0

Answer:

its 9 three times just like you said how its 9×3 and if you draw 3 cricles and put 9 sticks in it it give you and total of 27

You might be interested in

Which verbal expression best represents the algebraic expression 6n + 5?

anyanavicka [17]

Answer:

six times a number plus five

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Using the order of operations, what should be done first to evaluate mc019-1.jpg?

stellarik [79]

Answer:

"Multiply –6 and 3"

Step-by-step explanation:

For order of operations, we follow the rule PEMDAS

We do PARENTHESIS first, then
Exponents, then
Multiplication, then
Division, then
Addition, then
Subtraction

In this problem, we have parenthesis, so (-6)(3) should be done first.

Hence, we should multiply -6 and 3.

8 0

3 years ago

Read 2 more answers

12.48 milliliters of medicine were separated into doses of 4 mL each. how many doses were made?

ivolga24 [154]

The number of doses are $\boxed{\bf3}$ , if each dose quantity is 4 mL and total medicine is 12.48 mL.

Further explanation:

The total quantity of the medicine in millilitres is 12.48.

The quantity of one dose in millilitres is 4.

To find the number of doses possible from 12.48 millilitres quantity of medicine with each doses has 4 millilitres quantity is calculated by the use of division.

Here, dividend is the quantity of all medicine and divisor is the quantity of each doses.

Substitute, number 12.48 for dividend and number 4 for divisor then obtain the quotient by the use of division as shown below.

$\begin{aligned}4\mathop{\left){\vphantom{1{12.48}}}\right.\!\!\!\!\overline{\,\,\,\vphantom 1{{12.48}}}}\limits^{\displaystyle\hfill\,\,\, {3.12}} \hfill\\\,\,\,\,\,\,\underline{12 \downarrow }\hfill\\\,\,\,\,\,\,\,\,\,04\hfill\\\,\,\,\,\,\,\,\,\,\,\,\,\underline{4\downarrow } \hfill\\\,\,\,\,\,\,\,\,\,\,\,\,08\hfill\\\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\underline8\hfill\\\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,0\hfill\\\end{aligned}$