So are teacher ‍ gave us the answer but she wants us to to the work and I have tried so hard and I can’t find it

Mathematics

1 answer:

SVEN [57.7K]2 years ago

8 0

In order to find the shaded region the first thing you have to do is find the area of the two small triangles, then find the area of the big triangle. Subtract the area of the small triangles from the big one and that is the area.

Step one: 11×12=132

Step two: 132÷2= 66

Step three: 66+66=132 (because there is two small triangles with same dimensions)

Step four: 40×15=300

Step five: 300-132=168

Answer 168m^2

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I am offering another 100 points

Ivahew [28]

Answer:

$\sf Since \;\sqrt{\boxed{64}}=\boxed{8}\;and\;\sqrt{\boxed{81}}=\boxed{9}\; \textsf{it is known that $\sqrt{75}$ is between}\\\\\sf \boxed{8}\;and\;\boxed{9}\;.$

Step-by-step explanation:

Perfect squares: 4, 9, 16, 25, 36, 49, 64, 81, 100, 121, ...

To find $\sf \sqrt{75}$ , identify the perfect squares immediately before and after 75:

64 and 81

$\begin{aligned}\sf As\;\; 64 < 75 < 81\; & \implies \sf \sqrt{64} < \sqrt{75} < \sqrt{81}\\&\implies \sf \;\;\;\;\;8 < \sqrt{75} < 9 \end{aligned}$

$\sf Since \;\sqrt{\boxed{64}}=\boxed{8}\;and\;\sqrt{\boxed{81}}=\boxed{9}\; \textsf{it is known that $\sqrt{75}$ is between}\\\\\sf \boxed{8}\;and\;\boxed{9}\;.$

See the attachment for the correct placement of $\sf \sqrt{75}$ on the number line.