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yarga [219]
3 years ago
15

Write 3-5 sentences about the process of the Difference of squares Factoring Method

Mathematics
1 answer:
lisabon 2012 [21]3 years ago
5 0
To factor a difference of squares, the following steps are undertaken: Check if the terms have the greatest common factor (GCF) and factor it out. Remember to include the GCF in your final answer. Determine the numbers that will produce the same results and apply the formula: a2– b2 = (a + b) (a – b) or (a – b) (a + b)
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I NEED HELP ASAP PLEASE NO LINKS!!!
Ludmilka [50]

Answer:

1/8

Step-by-step explanation:

I looked it up lol

8 0
3 years ago
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If y varies inversely as x, and y = 23 when x<br> 8, find y when x 4.
Virty [35]

Answer:

y = 46

Step-by-step explanation:

Given y varies inversely as x then the equation relating them is

y = \frac{k}{x} ← k is the constant of variation

To find k use the condition y = 23 when x = 8 , then

23 = \frac{k}{8} ( multiply both sides by 8 )

184 = k

y = \frac{184}{x} ← equation of variation

When x = 4 , then

y = \frac{184}{4} = 46

7 0
2 years ago
a rectangular prism has a square base with a side length of 10 inches. The volume of the prism is 1,600 cubic inches. Find the s
Liula [17]

Answer:

840 in^2

Step-by-step explanation:

If the base is square and the side length is 10 inches, the areas of the base and of the top combined is 2(100 in^2).

The height of the prism comes from dividing the volume, 1600 in^3, by the area of the base, 100 in^2:  It is 16 in.  Then the combined areas of the four sides of the prism is 4(160 in^2).

The total surface area of the prsim is then 640 in^2 + 200 in^2, or 840 in^2.

7 0
2 years ago
Which of the following scenarios could be described by the equation below?<br><br><br><br> y=3x + 5
Eduardwww [97]

Answer:

yes

Step-by-step explanation:

have a nice day

8 0
2 years ago
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Write an equation of the line that passes through (5, −1) and is perpendicular to the line y=12x−1.
Lisa [10]

Step-by-step explanation:

solution

let,A(5,-1)

given

y=12x-1

or, y = 12 × x + (-1)

comparing it with y=mx+c

we get

x=1

y = c = -1

now

A(5,-1) and B(1,-1)

equation of line is,

(y-y1)/(x-x1) = (y2-y1)/(x2-x1)

or, (y+1)/(x-5) = (-1+1)/(1-5)

or, (y+1)/(x-5) = 0/-4

cross multiply

-4y-4 = 0

or, 0=4y+4

or, 4y+4=0 is the required eqn

I think this is the process and answer too.

I hope this helps you

4 0
3 years ago
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