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yarga [219]
3 years ago
15

Write 3-5 sentences about the process of the Difference of squares Factoring Method

Mathematics
1 answer:
lisabon 2012 [21]3 years ago
5 0
To factor a difference of squares, the following steps are undertaken: Check if the terms have the greatest common factor (GCF) and factor it out. Remember to include the GCF in your final answer. Determine the numbers that will produce the same results and apply the formula: a2– b2 = (a + b) (a – b) or (a – b) (a + b)
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0.9/0.5 = a/10 Plz help
jonny [76]

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18

Step-by-step explanation:

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7 0
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Read 2 more answers
Find all solutions and solutions in interval[0,2pi)
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sin(2x)-\sqrt{3}cos(x)=0\implies 2sin(x)cos(x)-cos(x)\sqrt{3}=0
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\stackrel{\stackrel{common}{factor}}{cos(x)}[2sin(x)-\sqrt{3}]=0\\\\
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7 0
3 years ago
Using the quadratic formula to solve x2 + 20 = 2x, what are the values of x?
jeka94

by Quadratic formula , x^2 + 20 = 2x , values of x are x = 1 \pm (1)i\sqrt{19}} . None of mentioned options are correct according to question!

<u>Step-by-step explanation:</u>

Here we have , expression  x2 + 20 = 2x or , x^2 + 20 = 2x .

We know that Quadratic formula is :

x = \frac{-b \pm \sqrt{b^{2}-4ac}}{2a}

x^2 + 20 = 2x

⇒ x^2-2x+20=0

a=1\\b=-2\\c=20

Putting this value in equation x = \frac{-b \pm \sqrt{b^{2}-4ac}}{2a} :

⇒ x = \frac{-b \pm \sqrt{b^{2}-4ac}}{2a}

⇒ x = \frac{-(-2) \pm \sqrt{(-2)^{2}-4(1)(20)}}{2(1)}

⇒ x = \frac{2 \pm \sqrt{4-80}}{2}

⇒ x = (\frac{2 \pm 2i\sqrt{19}}{2})

⇒ x = 1 \pm (1)i\sqrt{19}}

Therefore , by Quadratic formula , x^2 + 20 = 2x , values of x are x = 1 \pm (1)i\sqrt{19}} . None of mentioned options are correct according to question!

7 0
3 years ago
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