Well 6×12=72. I don't know what the original tank size was but subtract the original from this one to get your answer.
Given:
The bases of trapezoid measuring 4 m and 12 m.
To find:
The median of the trapezoid.
Solution:
The median of the trapezoid is the average of its bases.
![\text{Median}=\dfrac{\text{Upper base + Lower base}}{2}](https://tex.z-dn.net/?f=%5Ctext%7BMedian%7D%3D%5Cdfrac%7B%5Ctext%7BUpper%20base%20%2B%20Lower%20base%7D%7D%7B2%7D)
The bases of trapezoid measuring 4 m and 12 m. So, the median of the trapezoid is:
![\text{Median}=\dfrac{4+12}{2}](https://tex.z-dn.net/?f=%5Ctext%7BMedian%7D%3D%5Cdfrac%7B4%2B12%7D%7B2%7D)
![\text{Median}=\dfrac{16}{2}](https://tex.z-dn.net/?f=%5Ctext%7BMedian%7D%3D%5Cdfrac%7B16%7D%7B2%7D)
![\text{Median}=8](https://tex.z-dn.net/?f=%5Ctext%7BMedian%7D%3D8)
Therefore, the correct option is C.
Answer:
![\sf \dfrac{17}{25}](https://tex.z-dn.net/?f=%5Csf%20%5Cdfrac%7B17%7D%7B25%7D)
Step-by-step explanation:
<h3>Trigonometry:</h3>
![\sf \boxed{\bf Tan \ B=\dfrac{oppoiste \ side \ to \ Tan \ B}{hypotenuse}}](https://tex.z-dn.net/?f=%5Csf%20%5Cboxed%7B%5Cbf%20Tan%20%5C%20B%3D%5Cdfrac%7Boppoiste%20%5C%20side%20%5C%20to%20%5C%20Tan%20%5C%20B%7D%7Bhypotenuse%7D%7D)
![\sf tan \ B =\dfrac{17}{25}](https://tex.z-dn.net/?f=%5Csf%20tan%20%5C%20B%20%3D%5Cdfrac%7B17%7D%7B25%7D)