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3 years ago

What is the speed of sound in a vacuum?

2 answers:

7 0

Since a vacuum is empty space, there is no medium for the sound to travel through. The speed of sound in air mainly depends on the temperature of the air. On average, it is about 343 meters per second (1,125 feet per second),

spayn [35]3 years ago

6 0

The speed of sound in vacuum is zero meters per second. Without a physical medium, sound can't propagate, so it can never get from here to there, no matter how short the distance is.

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A vertical spring with a spring constant of 310 N/m is mounted on the floor. From directly above the spring, which is unstrained

EleoNora [17]

Answer:

7.3cm above the compressed spring.

Explanation:

We can use the conservation energy theorem to solve this problem:

$U_{1}+K_1=U_e+U_2+K_2\\m*g*h+0=\frac{1}{2}k*x^2+0+0\\\\h=\frac{k*x^2}{2*m*g}\\\\h=\frac{310N/m*(3.6*10^{-2})^2}{2*0.28kg*9.8m/s^2}\\\\h=0.073m$

The block was dropped 7.3cm above the compressed spring.

8 0

3 years ago

Solving equation for the quantity indicated

Slav-nsk [51]

T = (vf -vo)/a. .......

7 0

3 years ago

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In an RLC series circuit that includes a source of alternating current operating at fixed frequency and voltage, the resistance

maw [93]

Answer:

Capacitive Reactance is 4 times of resistance

Solution:

As per the question:

R = $X_{L} = j\omega L = 2\pi fL$

where

R = resistance

$X_{L} = Inductive Reactance$

f = fixed frequency

Now,

For a parallel plate capacitor, capacitance, C:

$C = \frac{\epsilon_{o}A}{x}$

where

x = separation between the parallel plates

Thus

C ∝ $\frac{1}{x}$

Now, if the distance reduces to one-third:

Capacitance becomes 3 times of the initial capacitace, i.e., x' = 3x, then C' = 3C and hence Current, I becomes 3I.

Also,

$Z = \sqrt{R^{2} + (X_{L} - X_{C})^{2}}$

Also,

Z ∝ I

Therefore,

$\frac{Z}{I} = \frac{Z'}{I'}$

$\frac{\sqrt{R^{2} + (R - X_{C})^{2}}}{3I} = \frac{\sqrt{R^{2} + (R - \frac{X_{C}}{3})^{2}}}{I}$

${R^{2} + (R - X_{C})^{2}} = 9({R^{2} + (R - \frac{X_{C}}{3})^{2}})$

${R^{2} + R^{2} + X_{C}^{2} - 2RX_{C} = 9({R^{2} + R^{2} + \frac{X_{C}^{2}}{9} - 2RX_{C})$

Solving the above eqn:

$X_{C} = 4R$

6 0

3 years ago

A hollow ball with a diameter of 3.81 cm has an average density of 0.0842 g/cm3. What force must be applied to hold it stationar

vfiekz [6]

Answer:

0.26

Explanation:

Given that :

Diameter of ball = 3.81 cm = 3.81/100 = 0.0381 m

Radius (r) = 0.0381 / 2 = 0.01905 m

Average density of ball (Db) = 0.0842 g/cm³ = (0.0842 / 1000)kg / 10^-6 = 0.0842/ 1000 * 10^6 = 84.2kg/m³

Density of water (Dw) = 1000kg/m³

Volume of hollow ball: (4/3) * pi * r³

V = (4/3) * π * 0.01905^3

V = 0.0000289583 m³

Required force = (Dw * V * g) - (Db * V * g)

= (1000 * 0.0000289583 * 9.8) - (84.2 * 0.0000289583 * 9.8)

= 0.259896109172

= 0.2598 N

6 0

3 years ago

What is the definition of force according to Newton's first law of motion?

11111nata11111 [884]

Newton's first law states that every object will remain at rest or in uniform motion in a straight line unless compelled to change its state by the action of an external force

8 0

3 years ago

Read 2 more answers