All categories

3 years ago

3. Which of the following processes provides the water necessary for human consumption?

Physics

2 answers:

hram777 [196]3 years ago

6 0

Answer:

precipitation is the answer..

Explanation:

precipitation is any product of the condensation of atmospheric water vapor that falls under gravitational pull from clouds. The main forms of precipitation include drizzling, rain, sleet, snow, ice pellets, graupel and hail.

WARRIOR [948]3 years ago

3 0

Precipitation, didn’t we all learn this in like 4th or 5th grade?

You might be interested in

PE=?, m=.6kg, g=10m/s2, h=35m<br><br> PLS HELP I NEED THIS DONE

Karo-lina-s [1.5K]

210J

PE is mgh in this context.

7 0

4 years ago

Two students race up a flight of steps together. "Student A" reaches the top of the steps 2 seconds ahead of

oksano4ka [1.4K]

Um student a because they were there a few seconds ahead

3 0

3 years ago

1. Explain who is doing more work and why: a bricklayer carrying bricks and placing them on the wallof a building being

Basile [38]

Both are doing because they have chorus

7 0

2 years ago

Give an example of a Claim.

Olin [163]

Answer:

Yeah

Explanation:

Look at the pic!!

5 0

3 years ago

Two astronauts, each with a mass of 50 kg, are connected by a 7 m massless rope. Initially they are rotating around their center

kiruha [24]

Answer:

The angular velocity is $w_f = 1.531 \ rad/ s$

Explanation:

From the question we are told that

The mass of each astronauts is $m = 50 \ kg$

The initial distance between the two astronauts $d_i = 7 \ m$

Generally the radius is mathematically represented as $r_i = \frac{d_i}{2} = \frac{7}{2} = 3.5 \ m$

The initial angular velocity is $w_1 = 0.5 \ rad /s$

The distance between the two astronauts after the rope is pulled is $d_f = 4 \ m$

Generally the radius is mathematically represented as $r_f = \frac{d_f}{2} = \frac{4}{2} = 2\ m$

Generally from the law of angular momentum conservation we have that

$I_{k_1} w_{k_1}+ I_{p_1} w_{p_1} = I_{k_2} w_{k_2}+ I_{p_2} w_{p_2}$

Here $I_{k_1 }$ is the initial moment of inertia of the first astronauts which is equal to $I_{p_1}$ the initial moment of inertia of the second astronauts So

$I_{k_1} = I_{p_1 } = m * r_i^2$

Also $w_{k_1 }$ is the initial angular velocity of the first astronauts which is equal to $w_{p_1}$ the initial angular velocity of the second astronauts So

$w_{k_1} =w_{p_1 } = w_1$

Here $I_{k_2 }$ is the final moment of inertia of the first astronauts which is equal to $I_{p_2}$ the final moment of inertia of the second astronauts So

$I_{k_2} = I_{p_2} = m * r_f^2$

Also $w_{k_2 }$ is the final angular velocity of the first astronauts which is equal to $w_{p_2}$ the final angular velocity of the second astronauts So