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tankabanditka [31]
3 years ago
11

During which type of collision do the two objects stick together?

Physics
1 answer:
inysia [295]3 years ago
6 0

Answer:

D. Perfectly inelastic

Explanation:

Kinetic energy is lost so the two bodies stick together.

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A 2 kg object has a specific heat capacity of 1,700 J/(kg \cdot⋅oC)
Nutka1998 [239]

The amount of heat needed to raise the temperature of a 2kg object from 15°C to 25°C is 34000J.

HOW TO CALCULATE SPECIFIC HEAT CAPACITY:

  • The amount of heat absorbed by an object can be calculated by using the following expression:

  • Q = m.c.∆T

Where;

  1. Q = amount of heat absorbed or released (J)
  2. m = mass of object
  3. c = specific heat capacity (J/g°C)
  4. ∆T = change in temperature (°C)

  • According to this question, 2 kg object has a specific heat capacity of 1,700J/kg°C and was raised from a temperature of 15 Celsius to 25 Celsius. The heat absorbed is calculated as follows:

  • Q = 2 × 1700 × {25 - 15}

  • Q = 3400 × 10

  • Q = 34000J

  • Therefore, the amount of heat needed to raise the temperature of a 2kg object from 15°C to 25°C is 34000J.

Learn more about how to calculate heat absorbed at: brainly.com/question/11194034?referrer=searchResults

8 0
2 years ago
A group of physics students hypothesize that for an experiment they are performing, the speed of an object sliding down an incli
goblinko [34]

Answer:

v = 2.974

Explanation:

Perhaps the formula should be

v = √(2*g*d (sin(θ) - uk*cos(θ) )                    This is a bit easier to read.

v = √(2* 9.80*0.725(0.707 - 0.12*0.707) )   Substitute values. Find 2*g*d

v = √14.21 * (0.707 - 0.0849)                        Figure out Sin(θ) - uk cos(θ)  

v = √14.21 * (0.6222)

v = √8.8422                                                  Take the square root of the value

v = 2.974

6 0
4 years ago
Read 2 more answers
Subduction occurs as a result of:__________
lutik1710 [3]

Answer:

a) Gravity pulling the older and denser lithosphere downward.

Explanation:

Earth's crust is made of plates which float on mantle . Plates are of two types

1 ) oceanic plates which are older and heavier 2 ) continental plates which are lighter . Continents are situated on continental plates. Due to relative motion , oceanic plate, because of its  heavy weight,  goes under lighter continental plate . This is called subduction.  

6 0
3 years ago
1) what is the potential energy at the end of the loop?
AlexFokin [52]

The potential energy at the end of the loop is equal to 0.3407 Joules.

<u>Given the following data:</u>

  • Mass of rock = 102.16 g to kg = 0.10216 kilogram.
  • Height of the loop = 34 cm to m = 0.34 meter.
  • Acceleration due to gravity = 9.8 m/s^2

<h3>What is potential energy?</h3>

Potential energy (P.E) refers to the energy that is possessed by an object due to its position (height) above planet Earth.

Mathematically, potential energy (P.E) is given by this formula;

P.E = mgh

<u>Where:</u>

  • m is the mass of an object.
  • g is the acceleration due to gravity.
  • h is the height of an object.

Substituting the given parameters into the formula, we have;

P.E = 0.10216 \times 9.81 \times 0.34

P.E = 0.3407 Joules.

<h3>What is kinetic energy?</h3>

Kinetic energy (K.E) refers to an energy that is possessed by a physical object due to its motion.

Mathematically, kinetic energy (K.E) is given by this formula;

K.E = \frac{1}{2} MV^2

<u>Note:</u> You'll have to calculate the velocity from the distance traveled by the car and photogate time in your experiment.

Based on the law of conservation of energy, we can deduce the following points:

  • Potential energy (P.E) is <u>highest</u> at the top of the loop while kinetic energy (K.E) is <u>lowest</u>.
  • Kinetic energy (K.E) is <u>highest</u> underneath the loop while potential energy (P.E) is <u>lowest</u>.

Read more on potential energy here: brainly.com/question/8664733

6 0
3 years ago
The string constrains the rotational and translational motion of the falling cylinder, given that it doesn't slip. what is the r
Sindrei [870]
<span>Answer: First we need to find the acceleration. torque on cylinder τ = T * r where T is the string tension; T = m(g - a) where a is the acceleration of the cylinder. Then τ = m(g - a)r But also τ = Iα. For a solid cylinder, I = ½mr², and if the string doesn't slip, then α = a / r, so τ = ½mr² * a/r = ½mra. Since τ = τ, we have m(g - a)r = ½mra → m, r cancel, leaving g - a = ½a g = 3a/2 a = 2g/3 where g, of course, is gravitational acceleration. We know that v(t) = a*t, so for our cylinder v(t) = 2gt / 3 ◄ linear velocity and ω = v(t) / r = 2gt / 3r ◄ angular velocity</span>
3 0
4 years ago
Read 2 more answers
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