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umka21 [38]
3 years ago
14

What is the difference between the experimental group and the control group? its like confusing

Physics
1 answer:
Doss [256]3 years ago
3 0
An experimental group is the group in the experiment that receives the variable that is being tested. Only one variable is tested at a time. The control group does not receive the test variable. the experimental groups are used to find the answers in a experiment
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Earlier we discussed the concept of isostasy, where lower density rocks rise higher than higher density rocks. How is the variat
Elena L [17]

The variation of water depth at spreading centers (ridges) controlled by isostasy  as convective cooling cools the rocks much more effectively the than heat conduction.

<h3>What is convective heat transfer?</h3>

When heat transfer takes place between the two fluids in direct or indirect contact.

The lithosphere cools when it moves away from the ridge axis by sea floor spreading. The cooler rocks have low density, so the sea floor gets deeper as the lithosphere gets more dense.

Thus, the convective cooling cools the rocks much more effectively the than heat conduction.

Learn more about convective heat transfer

brainly.com/question/10219972

#SPJ1

4 0
2 years ago
The force of gravity that the sun exerts on a planet is directed ______,
viktelen [127]

The force of gravity that the sun exerts on a planet is directed toward the sun. I am hoping that this answer has satisfied your query and it will be able to help you in your endeavor, and if you would like, feel free to ask another question.

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4 0
3 years ago
Simplicity expression
Volgvan
They have expression<span>, modesty, sex appeal, </span><span>simplicity.</span>
7 0
4 years ago
An asteroid orbits the Sun every 176 years. What is the asteroids average distance from the Sun? P ^ 2 = a ^ 3 where p = period
KatRina [158]

Answer:

The value is  x =  45.99 \  Au

Explanation:

From the question we are told that

   The period of the  asteroid is   T =  176 \ years = 176 * 365 * 24 * 60* 60 = 5.55*10^{9}\ s

Generally the average distance of the asteroid from the sun is mathematically represented as

            R = \sqrt[3]{ \frac{G M * T^2 }{4 \pi} }

Here M is the mass of the sun with a value  

        M  =  1.99*10^{30} \  kg

         G  is the gravitational constant with value  G  =  6.67 *10^{-11}  \  m^3 \cdot kg^{-1} \cdot  s^{-2}

           R = \sqrt[3]{ \frac{6.67 *10^{-11}  * 1.99*10^{30} * [5.55 *10^{9}]^2 }{4 * 3.142 } }

=>       R = 6.88 *10^{12} \  m

Generally

         1.496* 10^{11}  \  m  \to  1 Au (Astronomical \  unit )

So

          R = 6.88 *10^{12} \  m \ \ \ \ \to \ \   x \  Au

=>      x =  \frac{6.88 *10^{12}}{1.496 *10^{11}}

=>       x =  45.99 \  Au

       

7 0
3 years ago
How do you solve for this
Leya [2.2K]

Answer:

mejekekejenenbdhdhdbhr dhshshehwhhesheu d

Explanation:

m sbshsgsgys hehehehehe Ed

8 0
3 years ago
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