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Usimov [2.4K]
3 years ago
15

If 80% of a number is 100 what is 20% of that same number

Mathematics
1 answer:
Marina86 [1]3 years ago
8 0
We can rewrite these percentages in decimal form. That what we can write an equation to solve. A percentage is a decimal that is multiplied by 100. So to reverse that, let us divide by 100:

\frac{80}{100}=0.8 and \frac{20}{100} =0.2

So we know that 80% = 0.8, and 20% = 0.2.

An equation we can write for the question is the following.

0.8*x=100, where x is the 'mystery' number.

So let us then solve for x:

x= \frac{100}{0.8}=125

So now we know that x = 125. Let us then create a second equation and solve the question:

0.2*125=y, where y is the answer that the question is looking for.

Let us then solve for y:

y=0.2*125=25.

So now we know that the answer to the question is 25.
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Answer:

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Step-by-step explanation:

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How do you solve this
Katyanochek1 [597]
Add it together. You find area with base times height!!!
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Solve for x. -1/2 (x+5) = 2x -3/2
Pani-rosa [81]

Answer is a Decimal: x=-0.4

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3 years ago
PLEASE ANSWER ASAP WORTH 100 points get it right please
Trava [24]

Answer:

See below.

Step-by-step explanation:

Part A:

triangle QPR and triangle PSR are similar

Part B:

Triangle QPR is a right triangle with right angle QPR.

Triangle SPR is a right triangle with right angle PSR.

Angle QPR of triangle QPR corresponds to and is congruent to angle PSR of triangle PSR.

Angle R of triangle QSR corresponds to and is congruent to angle R of triangle PSR.

The similar triangles by AA Similarity are

triangle QPR and triangle PSR

Part C:

QR/PR = PR/SR

16/PR = PR/4

PR² = 16 * 4

PR² = 64

PR = 8

8 0
2 years ago
The table shows the results of an experiment in which subjects taking either a drug or a placebo either reported fatigue or did
Lady bird [3.3K]

Answer:

Therefore, the correct options are;

-P(fatigue) = 0.44

P(fatigue \left |  \right drug) = 0.533

--P(drug and fatigue) = 0.32

P(drug)·P(fatigue) = 0.264

Step-by-step explanation:

Here we have that for dependent events,

P(A \, and \, B)= P(A)\times  P(B\left |  \right A )

From the options, we have;

P(fatigue \left |  \right drug) = 0.533

P(drug) = 0.6

P(drug and fatigue) = 0.32

Therefore

P(drug and fatigue) = P(drug)×P(fatigue \left |  \right drug)  

= 0.6 × 0.533 = 0.3198 ≈ 0.32 = P(drug and fatigue)

Therefore, the correct options are;

-P(fatigue) = 0.44

P(fatigue \left |  \right drug) = 0.533

--P(drug and fatigue) = 0.32

P(drug)·P(fatigue) = 0.264

Since P(fatigue) = 0.44 ∴ P(drug) = 0.264/0.44 = 0.6.

4 0
3 years ago
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