Step-by-step explanation:
please find the attached document
Assume (a,b) has a minimum element m.
m is in the interval so a < m < b.
a < m
Adding a to both sides,
2a < a + m
Adding m to both sides of the first inequality,
a + m < 2m
So
2a < a+m < 2m
a < (a+m)/2 < m < b
Since the average (a+m)/2 is in the range (a,b) and less than m, that contradicts our assumption that m is the minimum. So we conclude there is no minimum since given any purported minimum we can always compute something smaller in the range.
Step-by-step explanation:
There are a total of 4 + 1 + 9 + 6 = 20 cookies. So the probabilities of each type for a random cookie are:
P(oatmeal raisin) = 4/20 = 1/5
P(sugar) = 1/20
P(chocolate chip) = 9/20
P(peanut butter) = 6/20 = 3/10
The answer to your question is false
-3 is further away from 0 because if you graph it on a number line, it will show that -3 is one unit further from 0 than -2.
