How do you solve this
1 answer:
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Answer:
The value of x lies between 20 and 40 and value of y lies between -20 and 10
Step-by-step explanation:
We are given that
....(1)
...(2)
First we convert inequality equation into equality equation to find the solution of the given system of inequality equation.
Therefore, we can write as
...(3)
...(4)
Adding equation (3) and (4) we get
Substitute y=10 in equation (3) we get
(30,10) is the intersect point of two equation.
Put x=0 in equation (3)
Substitute y=0 in equation (3)
Substitute x=0 in equation (4)
Substitute y=0 in equation (4)
Substitute x=0 and y=40 and in equation (1)
Hence, the equation is true.Therefore, the shaded region below the line.
Substitute x=0 and y=-20 in equation (2)
The equation is true. Hence, the shaded region is below the line.
Hence, the value of x lies between 20 and 40 and value of y lies between -20 and 10.
<u>ANSWER:</u>
The price of senior citizen ticket is $4 and price of child ticket is $7.
<u>SOLUTION: </u>
Given, first day of sales the school sold 3 senior citizen tickets and 9 child tickets for a total of $75.
The school took in $67 on the second day by selling 8 senior citizen tickets and 5 child tickets.
We need to find what is the price each of one senior citizen tickets and one child tickets.
Let, the price of senior citizen ticket be "x" and price of child ticket be "y"
Then according to the given information,
3x + 9y = 75
x + 3y = 25 [by cancelling the common term 3.
x = 25 – 3y ---- (1)
And, 8x + 5y = 67 ---- (2)
Substitute (1) in (2)
8(25 – 3y) + 5y = 67
200 – 24y + 5y = 67
5y – 24y = 67 – 200
-19y = -133
y =
y = 7
Now substitute y value in (1)
x = 25 – 3(7)
x = 25 – 21 = 4
Hence, the price of senior citizen ticket is $4 and price of child ticket is $7.