Answer:
To calculate the radius of a circle by using the circumference, take the circumference of the circle and divide it by 2 times π.
Step-by-step explanation:
3x + 10 < 3
3x + 7 < 0
3x < -7
x < -7/3 = -2.3333...
or
2x - 5 >= 5
2x >= 10
x >= 5
x < -7/3 or x >= 5
Answer:
Step-by-step explanation:
√121 = 11
√900 = √30^2 = 30
∛125 = ∛5^3 = 5
∛729 = ∛9^3 = 9
complette the square to get vertex form or y=a(x-h)^2+k
(h,k) is vertex
1. group x terms, so for y=ax^2+bx+c, do y=(ax^2+bx)+c
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2, factor out the leading coefinet (constant in front of the x^2 term), basicallly factor out a
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3. take 1/2 of the linear coefient (number in
front of the x), and square it ,then add negative and positive of it
inside parnthases
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4. complete the squre and expand
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so
y=-1/4x^2+4x-19
group
y=(-1/4x^2+4x)-19
undistribute -1/4
y=-1/4(x^2-16x)-19
take 1/2 of -16 and squer it to get 64 then add neg and pos inside
y=-1/4(x^2-16x+64-64)-19
factorperfect square
y=-1/4((x-8)^2-64)-19
expand
y=-1/4(x-8)^2+16-19
y=-1/4(x-8)^2-3
vertex is (8,-3)
(sqrt7)^6x = 49x - 6
There is no easy way to solve this . Drawing a graph will give a good approximation.
Draw y = (sqrt7)66x
and y = 49x - 6 and see where they intersect
Ill draw it on desmos graphing tool and give you the link.
