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3 years ago

Write the equation of a line through point (-5,1) and perpendicular to 2x - 3y = 6.

Mathematics

1 answer:

zubka84 [21]3 years ago

4 0

Answer:

y = 2/3x - 2

Step-by-step explanation:

Step 1:

y = mx + b Slope Intercept Form

Step 2:

2x - 3y = 6 Equation

Step 3:

- 3y = - 2x + 6 Subtract 2x on both sides

Step 4:

y = 2/3x - 2 Divide - 3 on both sides

Answer:

y = 2/3x - 2

Hope This Helps :)

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If sin A = 3/8, find the value of cosec A - sec A.

alexira [117]

Answer:

$\csc A - \sec A = \dfrac 83 + \dfrac{8}{\sqrt{55}}\\\\\csc A - \sec A = \dfrac 83 - \dfrac{8}{\sqrt{55}}$

Step by step explanation:

$\text{Given that,}\\\\~~~~~~\sin A = \dfrac 38 \\\\\implies \sin^2 A = \dfrac 9{64}\\\\\implies 1 - \cos^2 A = \dfrac{9}{64}\\\\\implies \cos ^2 A = 1 - \dfrac 9{64}\\\\\implies \cos^2 A = \dfrac{55}{64}\\\\\implies \cos A =\pm\sqrt{\dfrac{55}{64}}\\ \\\implies \cos A = \pm\dfrac{\sqrt{55}}8\\\\$

$\implies \dfrac 1{\cos A} = \pm\dfrac{8}{\sqrt{55}}$

$\text{Now,}\\\\\csc A - \sec A\\\\=\dfrac{1}{\sin A}- \dfrac{1}{\cos A}\\\\=\dfrac 83 -\left(\pm \dfrac 8{\sqrt {55}} \right)\\ \\\text{Hence,}\\\\\csc A - \sec A = \dfrac 83 + \dfrac{8}{\sqrt{55}}\\\\\csc A - \sec A = \dfrac 83 - \dfrac{8}{\sqrt{55}}$

6 0

2 years ago

In the diagram below AFB is congruent to EFD if EFD = 5x + 6, DFC = 19x - 15, and EFC = 17x + 19, find AFE

yanalaym [24]

The angle m∠AFE is 128 degrees.

<h3>How to find angles?</h3>

∠AFB ≅ ∠EFD

∠EFD = 5x + 6

m∠DFC = (19x - 15)°

m∠EFC = (17x + 19)°

m∠AFE = ?

m∠AFB + m ∠EFD + m∠AFE = 180

Therefore,

5x + 6 + 5x + 6 + m∠AFE = 180

5x + 5x + 6 + 6 + m∠AFE = 180

10x + 12 + m∠AFE = 180

10x + m∠AFE = 180 - 12

10x + m∠AFE = 168

m∠AFE = 168 - 10x

m∠EFC = m ∠EFD + m∠DFC

17x + 19 = 5x + 6 + 19x - 15

17x - 5x - 19x = 6 - 15 - 19

-7x = - 28

x = 28 / 7

x = 4

Therefore,

m∠AFE = 168 - 10x

m∠AFE = 168 - 10(4)

m∠AFE = 168 - 40

m∠AFE = 128°

Therefore, the angle m∠AFE = 128°

learn more on angles here: brainly.com/question/13212279

#SPJ1

7 0

2 years ago

Solve for x: -4X – 4 = -4(X + 2)

tester [92]

Answer:

there are no solutions

Step-by-step explanation:

3 0

3 years ago

The 6th term of a gp is -2/29,and it's first term is 18.what is the common ratio

Ymorist [56]

Answer:

-0.329

Step-by-step explanation:

The formula for Geometric ratio is

an = ar^n - 1

Where

a = First term = 18

r = Common ratio = ?

n = Number of term= 6

Hence

a6 = 18 × r^6-1

From the question

a6 = -2/29

Hence:

-2/29 = 18 × r^6-1

-2/29 = 18 × r⁵

Divide both sides by 18

-2/29 ÷ 18 = 18 × r⁵/18

-2/29 × 1/18 = r⁵

r⁵ = -1/261

Take the fifth root of both sides

⁵√(r⁵) = ⁵√(-1/261)

r = -0.3286032834

Approximately = -0.329

Therefore, Common ratio = -0.329

7 0

3 years ago

Help please asap will mark brainliest !

Ber [7]

Answer:

b = 29

Step-by-step explanation:

C x D = A x B

15(11x - 91) = 7(2x + 10)

165x - 1365 = 14x + 70

add 1365 to both sides of the equation:

165x = 14x + 1435

subtract 14x from both sides:

151x = 1435

divide both sides by 151:

x = 9.5

b = 2(9.5) + 10 = 29

8 0

3 years ago