Answer:
Completion to the first table for 
is {-1, 1, 3, 5}
Completion to the second table for 
is { -8, -2, 4, 10}
the option is x=-6
Step-by-step explanation:
Hope this helps and is correct.
The values which could be the slope of the line are numbers > 0.
<h3>Which values could be the slope of the line?</h3>
According to the task content, it follows that the given line originates from the lower left quadrant and continues through the upper right quadrant.
It therefore follows that the line is ascending from left to right in which case, the slope of the line is positive.
Hence, the possible values of the slope include the set of numbers greater than 0.
Read more on slope of lines;
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700+20+1 i'm not too sure but i hope this helps
We have that
y = 2x + 8
for x=1-----------> y=2*1+8=10
for x=2-----------> y=2*2+8=12
for x=3-----------> y=2*3+8=14
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.
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the equation y = 2x + 8 ----------- > defines y as a function of x, because <span>for each x there is only one value of y</span>.
the answer is
yes, the equation y = 2x + 8 defines y as a function of x
Answer: see proof below
<u>Step-by-step explanation:</u>
Given: A + B + C = π → C = π - (A + B)
→ sin C = sin(π - (A + B)) cos C = sin(π - (A + B))
→ sin C = sin (A + B) cos C = - cos(A + B)
Use the following Sum to Product Identity:
sin A + sin B = 2 cos[(A + B)/2] · sin [(A - B)/2]
cos A + cos B = 2 cos[(A + B)/2] · cos [(A - B)/2]
Use the following Double Angle Identity:
sin 2A = 2 sin A · cos A
<u>Proof LHS → RHS</u>
LHS: (sin 2A + sin 2B) + sin 2C
![\text{Factor:}\qquad \qquad \qquad 2\sin C\cdot [\cos (A-B)+\cos (A+B)]](https://tex.z-dn.net/?f=%5Ctext%7BFactor%3A%7D%5Cqquad%20%5Cqquad%20%5Cqquad%202%5Csin%20C%5Ccdot%20%5B%5Ccos%20%28A-B%29%2B%5Ccos%20%28A%2BB%29%5D)
LHS = RHS: 4 cos A · cos B · sin C = 4 cos A · cos B · sin C 
