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Write an inequality to describe the region. the region between the yz-plane and the vertical plane x = 3

deff fn [24]

Write an inequality to describe the region is x < 0 < 3

Inequalities in three dimensions:

When an inequality representing a region in three dimensions contains only one of the three variables, then the other two variables have no restrictions. We use inequalities to describe solid regions in three dimensions.

Answers and Explanation:

The y z - plane is represented by the equation x = 0

As the region is between this plane and the vertical plane x = 3, we will get the inequality 0 < 0 < 3

Thus, the desired inequality is

0 < 0 < 3.

Learn more about inequalities at:

brainly.com/question/14408811

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4 0

2 years ago

I need need help on the double. #pawpatrol

worty [1.4K]

K-7.2>2.1.
+7.2 +7.2
------------------
k> 9.3
are you suppose to solve for k?

3 0

3 years ago

Solve for a. a+|-23+6|=-32 Plz help

prisoha [69]

Answer:

a = -49

Step-by-step explanation:

a+|-23+6|=-32

Simplify the absolute value term

a+|-17|=-32

a+17=-32

Subtract 17 from each side

a +17-17 = -32-17

a = -49

5 0

3 years ago

Read 2 more answers

Seis manzanas y 8 peras cuestan $26. ¿Cuanto cuesta cada pera y cada manzana sabiendo que cada manzana cuesta el triple de lo qu

Rom4ik [11]

Usando un sistema de ecuaciones, se encuentra que

Cada manzana cuesta $3.
Cada pera cuesta $1.

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Un sistema de ecuaciones soluciona esta pergunta.
El custo de una manzana es x.
El custo de una pera es y.

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Seis manzanas y 8 peras cuestan $26, o sea, $6x + 8y = 26$
Cada manzana cuesta el triple de cada pera, o sea, $x = 3y$

-----------------------

Primero, encontramos el cuesto de una pera, substituyendo la segunda en la primera ecuación.

$6x + 8y = 26$

$6(3y) + 8y = 26$

$18y + 8y = 26$

$26y = 26$

$y = \frac{26}{26}$

$y = 1$

Cada pera cuesta $1.

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Cada manzana cuesta el triple de cada pera, o sea, $x = 3y = 3(1) = 3$ .

Cada manzana cuesta $3.

Se encuentra um problema similar en brainly.com/question/24646137

6 0

2 years ago

Which additional fact proves that ΔRST and ΔWXY are congruent if ∠T ≅ ∠Y and RT ≅ WY?

sergejj [24]

Answer:

Hence, option A is correct.

Step-by-step explanation:

We are asked to find the fact such that ΔRST and ΔWXY are congruent.

Since, we are given: ∠T ≅ ∠Y and RT ≅ WY.

we are given the following assumptions:

∠W = x + 5

∠X = 3x - 9

∠Y = 2x + 4

as we are given one angle congruent and one side congruent so in order to prove two triangles are congruent we just need to show that one more pair of angles are congruent.

so from the two triangle we could have that ∠W≅∠R

and ∠X≅∠S

Now we will go by options:

A)

if ∠S=2x+20 then as ∠X≅∠S.

3x-9=2x+20

x=29

∠S=∠W=78°.

B)

if ∠R = 2x + 20 then as ∠W≅∠R

⇒ x+5=2x+20

⇒ x= -15 which is not possible as it will make measure of angle W negative (x+5= -15+5= -10)

C)

if ∠S=2x^2+5 then as ∠X≅∠S.

⇒ 3x-9=2x^2+5

⇒ 2x^2-3x+14=0

on solving this quadratic equation we will get complex zeros.

Hence, option (C) is not correct.

D)

if ∠R = 2x

^2

+ 5 then as ∠W≅∠R.

⇒ x+5=

2x

^2

+ 5

⇒ 2x^2-x=0

⇒ x(2x-1)=0

either x=0 or x=1/2 which is not possible.

because by putting this x value in all the angles we see that sum of all the angles of a triangle is not equal to 180°

Hence, option D is not possible.

Hence, option A is correct.

4 0

3 years ago