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maksim [4K]
3 years ago
15

Factor the expression 20k + 50

Mathematics
1 answer:
Yuliya22 [10]3 years ago
4 0
Answer is 10(2k+5)

-----------------------------------

Work Shown:

20k+50 = 10*2k + 10*5
20k+50 = 10(2k+5)

Note how we can distribute the 10 back in to check our work
10(2k+5) = 10(2k)+10(5) = 20k+50
so that confirms we have the right answer

Another thing to notice is that 10 is the largest factor that we can pull out of 20k and 50. The value 10 is the GCF (greatest common factor) of 20 and 50.
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You have a $3175 student loan. Suppose you pay the loan off in two and a half years (30 months). Estimate your monthly payment b
finlep [7]

Answer:

$106

Step-by-step explanation:

The formula given for Monthly payment of a loan =

P × [ r (1 + r)/(1 + r)^n - 1

Where

r = interest rate

n = number of monthly payments

P = Present value of the loan

From the question,

r = interest rate, we were told to ignore hence, r = 0

P = $3,175

n = 30

Hence,

Amount to be paid monthly = P/n

= $3175/30

= $105.83

Approximately to the nearest dollars

= $106

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3 years ago
Molly works at an electronics store. Her last customer purchased a DVD player for $67.65 and five DVDs for $57.93, including tax
ra1l [238]
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3 years ago
Pat needs to paint an 8 ft x 36 ft rectangular wall. what is the area that she paints?
lora16 [44]

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5 0
3 years ago
According to the data, Vannessa mean quiz ...
damaskus [11]

Answer: x = 108

Given the below equation

x + 13 1/2 = 121 1/2

Firstly, we need to convert the mixed fraction into an improper fraction

\begin{gathered} x\text{ + 13}\frac{1}{2}\text{ = 121 }\frac{1}{2} \\ 13\frac{1}{2}\text{ = }\frac{(2\text{ x 13) + 1}}{2} \\ 13\text{ }\frac{1}{2}\text{ = }\frac{26\text{ + 1}}{2} \\ 13\frac{1}{2}\text{ = }\frac{27}{2} \\ 121\frac{1}{2}\text{ = }\frac{(2\text{ x 121) + 1}}{2} \\ 121\frac{1}{2}\text{ = }\frac{243}{2} \\ \text{Therefore, the new equation becomes} \\ x\text{ + }\frac{27}{2}\text{ = }\frac{243}{2} \\ \text{Isolate x} \\ x\text{ = }\frac{243}{2}\text{ - }\frac{27}{2} \\ \text{Common denominator = 2} \\ x=\text{ }\frac{243\text{ - 27}}{2} \\ x\text{ = }\frac{216}{2} \\ x\text{ = 108} \end{gathered}

8 0
1 year ago
Help with Pre Calculus
marshall27 [118]

Answer:

The first option

Step-by-step explanation:

The domain of a rational function should be all real numbers except for when the denominator is equal to 0. To find when the denominator is equal to 0 you simply need to find the zeroes of the denominator... but in this case you can do that through factoring and using the quadratic equation.

So first step is going to be to factor out the GCF, which in this case is x. This gives you the equation. x(2x^2-x-15). So one of the zeroes is when x=0. Now to find the other two zeroes you can use the quadratic equation which is x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\. So to find the other zeroes you simply plug the values in. a=2, b=-1, c=-15

x=\frac{-(-1)\pm\sqrt{(-1)^2-4(2)(-15)}}{2(2)}\\\\x=\frac{1\pm\sqrt{1-4(2)(-15)}}{4}\\\\x=\frac{1\pm\sqrt{121)}}{4}\\\\x=\frac{1\pm11}{4}\\\\x=\frac{12}{4}\\x=3\\\\x=\frac{-10}{4}\\x=-\frac{5}{2}

4 0
2 years ago
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