Whenever you want to write the equation of a parallel line through some point (h, k), you can ...
- remove any added constant in the original given equation
- replace x with (x-h)
- replace y with (y-k)
- rearrange the resulting equation to the form required by the problem.
Using this formula here, we get
... 2(y +5) = 3(x -2)
Your answer form requires you solve this for y.
... 2y + 10 = 3x -6 . . . . . eliminate parentheses
... 2y = 3x -16 . . . . . . . . subtract the constant on the left (10)
... y = (3/2)x -8 . . . . . . divide by 2
Answer:Use the slope −2 and the point (−4,−5) to find the y-intercept.
y=mx+b
⇒−5=(−2×−4)+b
⇒−5=8+b
⇒b=−13
Write the equation in slope intercept form as:
y=mx+b
⇒y=(−2)x−13
Hence, the equation of the line is y=−2x−13.
Step-by-step explanation:
Please make me brainliest :)
So slope intercept form is y=mx+b
m=slope b=y intercept
convert current equation to slpe intercept
y-4=x-8
add 4 to both sides
y=x-4
tada
Answer: 2 or B hope this helped!