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3 years ago

Write the equation for the perpendicular bisector of the given line segment.

Mathematics

1 answer:

spayn [35]3 years ago

4 0

Answer:

Step-by-step explanation:

find the equation of the segment two point (-5,5) and (-2,-4)

m=y2-y1/x2-x1 =5-(-4)/-5-(-2) =9/-3 = -3

find b : y= -3x+b

5 =-3(-5) +b

b=-10

the equation is : y=-3x-10

the perpendicular line is y=1/3 x -2/3

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luda_lava [24]

Answer:

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3 years ago

Find the missing value so that the two points have a slope of -2 (1,y)and (6,-5)

Dahasolnce [82]

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3 years ago

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Step-by-step explanation:

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2 years ago

Find out the number of combinations and the number of permutations for 8 objects taken 6 at a time. Express your answer in exact

umka2103 [35]

Solution:

The permutation formula is expressed as

$\begin{gathered} P^n_r=\frac{n!}{(n-r)!} \\ \end{gathered}$

The combination formula is expressed as

$\begin{gathered} C^n_r=\frac{n!}{(n-r)!r!} \\ \\ \end{gathered}$

where

$\begin{gathered} n\Rightarrow total\text{ number of objects} \\ r\Rightarrow number\text{ of object selected} \end{gathered}$

Given that 6 objects are taken at a time from 8, this implies that

$\begin{gathered} n=8 \\ r=6 \end{gathered}$

Thus,

Number of permuations:

$\begin{gathered} P^8_6=\frac{8!}{(8-6)!} \\ =\frac{8!}{2!}=\frac{8\times7\times6\times5\times4\times3\times2!}{2!} \\ 2!\text{ cancel out, thus we have} \\ \begin{equation*} 8\times7\times6\times5\times4\times3 \end{equation*} \\ \Rightarrow P_6^8=20160 \end{gathered}$

Number of combinations:

$\begin{gathered} C^8_6=\frac{8!}{(8-6)!6!} \\ =\frac{8!}{2!\times6!}=\frac{8\times7\times6!}{6!\times2\times1} \\ 6!\text{ cancel out, thus we have} \\ \frac{8\times7}{2} \\ \Rightarrow C_6^8=28 \end{gathered}$

Hence, there are 28 combinations and 20160 permutations.

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11 months ago

What is the equation of the blue graph?

Tanya [424]

G(x) = (x-2)^3
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3 years ago