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3 years ago

Thermal energy is the energy associated with

Chemistry

2 answers:

Maksim231197 [3]3 years ago

3 0

Is associated with heat

trapecia [35]3 years ago

3 0

Or in other words temperature being the actual answer but you gave him no options so he was close enough.

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Suppose of copper(II) acetate is dissolved in of a aqueous solution of sodium chromate. Calculate the final molarity of acetate

uranmaximum [27]

Answer:

0.0714 M for the given variables

Explanation:

The question is missing some data, but one of the original questions regarding this problem provides the following data:

Mass of copper(II) acetate: $m_{(AcO)_2Cu} = 0.972 g$

Volume of the sodium chromate solution: $V_{Na_2CrO_4} = 150.0 mL$

Molarity of the sodium chromate solution: $c_{Na_2CrO_4} = 0.0400 M$

Now, when copper(II) acetate reacts with sodium chromate, an insoluble copper(II) chromate is formed:

$(CH_3COO)_2Cu (aq) + Na_2CrO_4 (aq)\rightarrow 2 CH_3COONa (aq) + CuCrO_4 (s)$

Find moles of each reactant. or copper(II) acetate, divide its mass by the molar mass:

$n_{(AcO)_2Cu} = \frac{0.972 g}{181.63 g/mol} = 0.0053515 mol$

Moles of the sodium chromate solution would be found by multiplying its volume by molarity:

$n_{Na_2CrO_4} = 0.0400 M\cdot 0.1500 L = 0.00600 mol$

Find the limiting reactant. Notice that stoichiometry of this reaction is 1 : 1, so we can compare moles directly. Moles of copper(II) acetate are lower than moles of sodium chromate, so copper(II) acetate is our limiting reactant.

Write the net ionic equation for this reaction:

$Cu^{2+} (aq) + CrO_4^{2-} (aq)\rightarrow CuCrO_4 (s)$

Notice that acetate is the ion spectator. This means it doesn't react, its moles throughout reaction stay the same. We started with:

$n_{(AcO)_2Cu} = 0.0053515 mol$

According to stoichiometry, 1 unit of copper(II) acetate has 2 units of acetate, so moles of acetate are equal to:

$n_{AcO^-} = 2\cdot 0.0053515 mol = 0.010703 mol$

The total volume of this solution doesn't change, so dividing moles of acetate by this volume will yield the molarity of acetate:

$c_{AcO^-} = \frac{0.010703 mol}{0.1500 L} = 0.0714 M$

8 0

4 years ago

Which solution has the greater concentration?

WITCHER [35]

The higher concentrated solution is 0.250 mole LiCl dissolved in 250 ml of solution

( B).0.250mole of LiCl diluted in 250ml solution

Explanation:

Procedure to find the intensity of the solution:

To find the intensity of the solution, we have to use the following formula

M1V1=M2V2

250mL of a 0.500 M aqueous solution of LiCl is diluted with water

$M1V1=(250) \times (0.500)=125M$

250 ml of a 0.250M aqueous solution of LiCl is diluted with water

$M2V2=(250) \times (0.250)=62.5M$

Thus the PH level of a solution increases from ascending order, Therefore the Solution with 62.5M is a higher concentration than that of the solution with 125M.

7 0

4 years ago

This chart show the amount of radioactivity measured from three unknown isotopes. Which statement describes each of the isotopes

Natalija [7]

Answer: Isotope A was measured at day 24, Isotope B was measured at day 6, and Isotope C was measured at day 10.

Explanation:

The half-life time is defined as the time needed for the radioactive isotope to decay to the half of its initial concentration.

Isotope A: its starting weight 95 g and its ending measured weight is 5.9.

95 → 47.5 (half-life 1) → 23.75 (half-life 2) → 11.875 (half-life 3) → 5.9 (half-life 4).

It needs 4 half-lives to decay from 95 to 5.9.

half-life time of isotope A = 6 days.

the time taken to measure isotope A = (4 x 6 days) = 24 days.

Isotope B: its starting weight 20 g and its ending measured weight is 2.5.

20 → 10 (half-life 1) → 5 (half-life 2) → 2.5 (half-life 3).

It needs 3 half-lives to decay from 20 to 2.5.

half-life time of isotope B = 2 days.

the time taken to measure isotope B = (3 x 2 days) = 6 days.

Isotope C: its starting weight 45 g and its ending measured weight is 22.5.

45 → 22.5 (half-life 1)

It needs 1 half-life to decay from 45 to 22.5.

half-life time of isotope C = 10 days.

the time taken to measure isotope C = (1 x 10 days) = 10 days.

4 0

3 years ago

Read 2 more answers

FeCl2 Express your answers as ions separated by a comma.

Katen [24]

In this item, it is assume that we are to express the dissociation of the formula unit given to be FeCl₂ into its ionic components.

As seen in the chemical formula, the unit is composed of iron (Fe) and chlorine (Cl). The dissociation is written as follows;

FeCl₂ --> Fe²⁺ + Cl⁻

This equation is balanced by multiplying the appropriate component with a number that would equate the number of atoms in both sides of the equation.

 FeCl₂ --> Fe²⁺ + 2Cl⁻

6 0

3 years ago

Using the periodic table, choose the more reactive nonmetal. Br or As

vladimir2022 [97]

Br
First of all, As is a metalloid, not a nonmetal. Second of all, as the rows get higher on the periodic table, the elements are more reactive. As you move right on the periodic table, the elements become more reactive.

3 0

3 years ago