Given a 5.81g sample of H2 (FM =2.02), contained in a volume of 3.90L. How many atm of pressure would it have if the temperature
was 64 degrees celsius?
1 answer:
Answer:
The answer to your question is: P = 20.4 atm
Explanation:
Data
mass = 5.81 g
FM = 2.02
vol = 3.9 L
P = ?
T = 64°C = 337°K
R = 0.082 atm L / mol°K
Formula
P = nRT / V
Process
2.02 g ---------------- 1 mol
5.81 g ---------------- x
x = (5.81 x 1) / 2.02
x = 2.88 mol
P = (2.88)(0.082)(337) / 3.9
P = 20.4 atm
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