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4 years ago

Which solution has the greater concentration?

Chemistry

1 answer:

WITCHER [35]4 years ago

7 0

The higher concentrated solution is 0.250 mole LiCl dissolved in 250 ml of solution

( B).0.250mole of LiCl diluted in 250ml solution

<u>Explanation:</u>

<u>Procedure to find the intensity of the solution:</u>

To find the intensity of the solution, we have to use the following formula

M1V1=M2V2

250mL of a 0.500 M aqueous solution of LiCl is diluted with water

$M1V1=(250) \times (0.500)=125M$

250 ml of a 0.250M aqueous solution of LiCl is diluted with water

$M2V2=(250) \times (0.250)=62.5M$

Thus the PH level of a solution increases from ascending order, Therefore the Solution with 62.5M is a higher concentration than that of the solution with 125M.

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A 0.1014 g sample of a purified compound containing C, H, and, O was burned in a combustion apparatus and produced 0.1486 g CO2

Alina [70]

Answer: The empirical formula for the given compound is $CH_2O$

Explanation:

The chemical equation for the combustion of hydrocarbon having carbon, hydrogen and oxygen follows:

$C_xH_yO_z+O_2\rightarrow CO_2+H_2O$

where, 'x', 'y' and 'z' are the subscripts of Carbon, hydrogen and oxygen respectively.

We are given:

Mass of $CO_2=0.1486g$

Mass of $H_2O=0.0609g$

We know that:

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

For calculating the mass of carbon:

In 44 g of carbon dioxide, 12 g of carbon is contained.

So, in 0.1486 g of carbon dioxide, $\frac{12}{44}\times 0.1486=0.0405g$ of carbon will be contained.

For calculating the mass of hydrogen:

In 18 g of water, 2 g of hydrogen is contained.

So, in 0.0609 g of water, $\frac{2}{18}\times 0.0609=0.00677$ of hydrogen will be contained.

Mass of oxygen in the compound = (0.1014) - (0.0405 + 0.00677) = 0.054 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon = $\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{0.0405g}{12g/mole}=0.003375moles$

Moles of Hydrogen = $\frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{0.00677g}{1g/mole}=0.00677moles$

Moles of Oxygen = $\frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{0.054g}{16g/mole}=0.003375moles$

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.485 moles.

For Carbon = $\frac{0.003375}{0.003375}=1$

For Hydrogen = $\frac{0.00677}{0.003375}=2.00\times 2$

For Oxygen = $\frac{0.003375}{0.003375}=1$

Step 3: Taking the mole ratio as their subscripts.

The ratio of C : H : O = 1 : 2 : 1

The empirical formula for the given compound is $C_1H_2O_1=CH_2O$

Thus, the empirical formula for the given compound is $CH_2O$

8 0

3 years ago

El osmio es un metal sólido que tiene una densidad

pentagon [3]

Respuesta:

4.42 × 10⁻⁶ m³

Explicación:

Paso 1: Información provista

Densidad del osmio (ρ): 22600 kg/m³

Masa de osmio (m): 100 g

Paso 2: Convertir 100 g a kilogramos

Usaremos el factor de conversion 1 kg = 1000 g.

100 g × 1 kg/1000 g = 0.100 kg

Paso 3: Calcular el volumen ocupado por 0.100 kg de osmio

La densidad es una propiedad intensiva, igual al cociente entre la masa y el volumen.

ρ = m/V

V = m/ρ

V = 0.100 kg / (22600 kg/m³) = 4.42 × 10⁻⁶ m³

5 0

3 years ago

Specific gravity of a vegetable oil is 0.85. What is its density?

elena-s [515]

I think its density is 850kg/m^3

6 0

3 years ago

Nitrogen dioxide reacts with water to form nitric acid and nitrogen monoxide according to the equation: 3NO2(g)+H2O(l)→2HNO3(l)+

Vesnalui [34]

Answer:

2 mol NO2

Explanation:

3NO2(g)+H2O(l)→2HNO3(l)+NO(g)

from reaction 3 mol 1 mol

given 11 mol 3 mol

for 3 mol NO2 ----- 1 mol H2O

for x mol NO2 ----- 3 mol H2O

3:x = 1:3

x = 3 *3/1 = 9 mol NO2

So, for 3 mol H2O are needed only 9 mol NO2.

But we have 11 mol NO2. So, NO2 is in excess, and

11 mol NO2 - 9 mol NO2 = 2 mol NO2 will be left after reaction.

3 0

3 years ago

Which of the fields below are significantly involved in food

Korolek [52]

Answer:

Explanation:

Genetic Engineering is a huge part in manipulating a foods property. Chemical engineering mostly the science with numbers in foods.

Biology is literally the life of the food.

6 0

3 years ago

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