Answer: 3/4
Step-by-step explanation:
Tangent is opp/adj
Therefore tan (x) = 18/24, which reduces to 3/4
Answer:
The 95% confidence interval for the mean number of words a third grader can read per minute is (23.8, 24.4).
Step-by-step explanation:
We have to find our 
level, that is the subtraction of 1 by the confidence interval divided by 2. So:
Now, we have to find z in the Z-table as such z has a p-value of 
.
That is z with a p-value of 
, so Z = 1.96.
Now, find the margin of error M as such
In which 
is the standard deviation of the population and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 24.1 - 0.3 = 23.8
The upper end of the interval is the sample mean added to M. So it is 24.1 + 0.3 = 24.4.
The 95% confidence interval for the mean number of words a third grader can read per minute is (23.8, 24.4).
Here, we are required to find the vertical and horizontal intercepts for r⁴ + s² − r s = 16.
The vertical and horizontal intercepts are s = ±4 and r = ±2 respectively.
According to the question;
- the r-axis is the horizontal axis.
- the s-axis is the vertical axis.
Therefore, to get the horizontal intercepts, r we set the vertical axis, s to zero(0).
- i.e s = 0
- the equation r⁴ + s² − r s = 16, then becomes;
- r⁴ = 16
- Therefore, r = ±2.
Also, to to get the vertical intercepts, s we set the horizontal axis, r to zero(0).
- i.e r = 0.
- the equation r⁴ + s² − r s = 16, then becomes;
- s² = 16.
- Therefore, s = ±4.
Therefore, the vertical and horizontal intercepts are s = ±4 and r = ±2 respectively.
Read more:
brainly.com/question/18466425
Answer:
The fraction or percentage of the applicants that we would expect to have a score of 400 or above is 77.34%
Step-by-step explanation:
Scores are normally distributed with a mean of 460 and a standard deviation of 80. For a value x, the associated z-score is computed as 
, therefore, the z-score for 400 is given by 
. To compute the fraction of the applicants that we would expect to have a score of 400 or above, we should compute the probability P(Z > -0.75) = 0.7734, i.e., the fraction or percentage of the applicants that we would expect to have a score of 400 or above is 77.34%
