How do you divide 12.92 by 3.4

Carlos find the absolute value of -5 3/10 and then find is the opposite of his answer Jason finds the opposite of -5 3/10 and th

a_sh-v [17]

we know that

$5 \frac{3}{10}= \frac{5*10+3}{10} = \frac{53}{10}$

Step 1

<u>Carlos's method</u>

1) <u>Find the absolute value of $-\frac{53}{10}$ </u>

$\left|-\frac{53}{10}\right|=\frac{53}{10}$

2) <u>Find the opposite</u>

$opposite=-\frac{53}{10}$

Step 2

<u>Jason's method</u>

1) <u>Find the opposite of $-\frac{53}{10}$ </u>

$opposite=\frac{53}{10}$

2) <u>Find the absolute value </u>

$\left|\frac{53}{10}\right|=\frac{53}{10}$

Step 3

<u>Compare the answers</u>

$\frac{53}{10} > -\frac{53}{10}$

therefore

<u>The answer is</u>

The greater value is obtained with the method of Jason

4 0

3 years ago

URGENT!!!!!

Anna11 [10]

h=20w

in one week hector works 20 hours

in two hector works 40 etc

h = hours and w = weeks. the money is just extra information.

h=20w works because if it has been two weeks we substitute the w with the number 2 and can solve

h=20(2)

h=20x2

h=40

This proves that the equation is true

7 0

3 years ago

The graph below shows the value of Edna's profits f(t), in dollars, after t months:

umka21 [38]

Since we know that the graph of our quadratic function has x-intercepts at (6,0) and (18,0), $x=6$ and $x=18$ are the zeroes of our quadratic. To find our quadratic we are going to factor each zero backwards and multiply them:
$x=6$
$x-6=0$
$x=18$
$x-18=0$

$(x-6)(x-18)=x^{2}-6x-18x+108$
$=x^{2}-24x+108$

Now that we have our quadratic function, we are going to use the average formula: $m= \frac{f(9)-f(3)}{9-3}$
$where$
$f(9)$ is the function evaluated at the <span>9th month
</span> $f(3)$ is the function evaluated at the 3rd month

$m= \frac{f(9)-f(3)}{9-3}$
$m= \frac{[9^{2}-24(9)+108]-[3^{2}-24(3)+108]}{9-3}$
$m= \frac{-27-45}{6}$
$m= \frac{-72}{6}$
$m=-12$

We can conclude that the closest approximate average rate of change for Edna's profits from the 3rd month to the 9th month is: <span>B. −11.63 dollars per month.</span>

6 0

3 years ago

Read 2 more answers

CAN SOMEBODY HELP ME PLEASE

Natasha_Volkova [10]

Answer:

vertex (3, -1)
y-intercept: (0, 8)
x-intercepts: (2, 0), (4, 0)

Step-by-step explanation:

You are being asked to read the coordinates of several points from the graph. Each set of coordinates is an (x, y) pair, where the first coordinate is the horizontal distance to the right of the y-axis, and the second coordinate is the vertical distance above the x-axis. The distances are measured according to the scales marked on the x- and y-axes.

__

<h3>Vertex</h3>

The vertex is the low point of the graph. The graph is horizontally symmetrical about this point. On this graph, the vertex is (3, -1).

<h3>Y-intercept</h3>

The y-intercept is the point where the graph crosses the y-axis. On this graph, the y-intercept is (0, 8).

<h3>X-intercepts</h3>

The x-intercepts are the points where the graph crosses the x-axis. You will notice they are symmetrically located about the vertex. On this graph, the x-intercepts are (2, 0) and (4, 0).

__

<em>Additional comment</em>

The reminder that these are "points" is to ensure that you write both coordinates as an ordered pair. We know the x-intercepts have a y-value of zero, for example, so there is a tendency to identify them simply as x=2 and x=4. This problem statement is telling you to write them as ordered pairs.

5 0

2 years ago

Prove that if b is a square matrix then b+b^t is symmetric

WARRIOR [948]

A matrix $\mathbf X$ is symmetric if $\mathbf X=\mathbf X^\top$ . We have

$(\mathbf B+\mathbf B^\top)^\top=\mathbf B^\top+(\mathbf B^\top)^\top=\mathbf B^\top+\mathbf B=\mathbf B+\mathbf B^\top$

and so $\mathbf B+\mathbf B^\top$ is indeed symmetric.

6 0

3 years ago