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Ivanshal [37]
3 years ago
12

Which real numbers are zeros of the function?

Mathematics
1 answer:
Galina-37 [17]3 years ago
7 0

Answer: 0, 1/3, -3, 3

Explanation:

I got this question right on k12.

<h2>sincerely, The greatest </h2>

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A N S W E R Q U I C K P L E A S E
chubhunter [2.5K]

Answer:

1. A

2. D

3. D

Step-by-step explanation:

The standard form of a parabola is

y=\frac{1}{4p}(x-h)^2+k            ..... (1)

Where, (h,k) is vertex, (h,k+p) is focus and y=k-p is directrix.

1. The directrix of a parabola is y=−8 . The focus of the parabola is (−2,−6) .

k-p=-8                   ...(a)

(h,k+p)=(-2,-6)

k+p=-6            .... (b)

h=-2

On solving (a) and (b),  we get k=-7 and p=1.

Put h=-2, k=-7 and p=1 in equation (1).

y=\frac{1}{4(1)}(x-(-2))^2+(-7)

y=\frac{1}{4}(x+2)^2-7

Therefore option A is correct.

2 The directrix of a parabola is the line y=5 . The focus of the parabola is (2,1) .

k-p=5                   ...(c)

(h,k+p)=(2,1)

k+p=1            .... (d)

h=2

On solving (c) and (d),  we get k=3 and p=-2.

Put h=2, k=3 and p=-2 in equation (1).

y=\frac{1}{4(-2)}(x-(2))^2+(3)

y=-\frac{1}{8}(x-2)^2+3

Therefore option D is correct.

3. The focus of a parabola is (0,−2) . The directrix of the parabola is the line y=−3 .

k-p=-3                   ...(e)

(h,k+p)=(0,-2)

k+p=-2            .... (f)

h=0

On solving (e) and (f),  we get k=-2.5 and p=0.5.

Put h=0, k=-2.5 and p=0.5 in equation (1).

y=\frac{1}{4(0.5)}(x-(0))^2+(-2.5)

y=\frac{1}{2}(x)^2-2.5

y=\frac{1}{2}(x)^2-\frac{5}{2}

Therefore option D is correct.

5 0
3 years ago
1.2 repeating as a fraction
Step2247 [10]
11/9 is what im thinking
3 0
3 years ago
I need help!! Find the area of each shaded segment. Round your answer to the nearest 10th
guajiro [1.7K]

Given:

θ = 60°

Radius = 8 in

To find:

The area of the shaded segment.

Solution:

Vertically opposite angles are congruent.

Angle for the shaded segment = 60°

<u>Area of the sector:</u>

$A=\pi r^2\times \frac{\theta}{360^\circ}

$A=3.14 \times 8^2\times \frac{60^\circ}{360^\circ}

A = 33.5 in²

Area of the sector = 33.5 in²

<u>Area of triangle:</u>

$A=\frac{1}{2} bh

$A=\frac{1}{2} \times 8\times 8

A = 32 in²

Area of the triangle = 32 in²

Area of segment = Area of sector - Area of triangle

                            = 33.5 in² - 32 in²

                            = 1.5 in²

The area of the shaded segment is 1.5 square inches.

8 0
3 years ago
A newspaper invited readers to call a telephone number and record their comments. The next day they reported that readers overwh
maks197457 [2]

Answer: Self selected sample

Step-by-step explanation:

They people chose themselves

4 0
3 years ago
3) A truck has 673 boxes of candies. Each box has a dozen candies in it. What is the total number of
jenyasd209 [6]

Answer:

8076 candies is the total number of candies on the truck

Step-by-step explanation:

  • Each box has a dozen candies in it means 1 box contains 12 candies.

If 1 box has 12 candies.

then 673 boxes shall have ( 673 * 12 ) = 8076 candies.

8 0
2 years ago
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