Question

If someone throws a 3 gram fry accelerating at 5 meter/second2, what is the fry’s force?

Answer 1

The force on the fry is $0.015 N$

Explanation:

We can find the force acting on the fry by using Newton's second law:

$F=ma$

where

F is the net force on the fry

m is its mass

a is its acceleration

For the fry in this problem,

$m=3 g = 0.003 kg$

$a=5.0 m/s^2$

Therefore, the force exerted on the fry is

$F=(0.003)(5)=0.015 N$

Learn more about Newton's second law here:

brainly.com/question/3820012

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