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saw5 [17]
3 years ago
14

If someone throws a 3 gram fry accelerating at 5 meter/second2, what is the fry’s force?

Physics
1 answer:
Arada [10]3 years ago
3 0

The force on the fry is 0.015 N

Explanation:

We can find the force acting on the fry by using Newton's second law:

F=ma

where

F is the net force on the fry

m is its mass

a is its acceleration

For the fry in this problem,

m=3 g = 0.003 kg

a=5.0 m/s^2

Therefore, the force exerted on the fry is

F=(0.003)(5)=0.015 N

Learn more about Newton's second law here:

brainly.com/question/3820012

#LearnwithBrainly

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At a picnic, there is a contest in which hoses are used to shoot water at a beach ball from three different directions. As a res
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Answer:

F₃ = 122.88 N

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Explanation:

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For y-component:

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F₃ = √F₃ₓ² + F₃y²

F₃ = √[(- 115 N)² + (- 43.3 N)²]

<u>F₃ = 122.88 N</u>

and the direction is given as:

θ₃ = tan⁻¹(F₃y/F₃ₓ) = tan⁻¹(-43.3 N/-115 N)

<u>θ₃ = 20.63°</u>

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