Answer:
Heat energy required (Q) = 3,000 J
Explanation:
Find:
Mass of water (M) = 200 g
Change in temperature (ΔT) = 15°C
Specific heat of water (C) = 1 cal/g°C
Find:
Heat energy required (Q) = ?
Computation:
Q = M × ΔT × C
Heat energy required (Q) = Mass of water (M) × Change in temperature (ΔT) × Specific heat of water (C)
Heat energy required (Q) = 200 g × 15°C × 1 cal/g°C
Heat energy required (Q) = 3,000 J
Answer:
2700
Explanation:
because calculate the minute1=60×45=2700
Answer:
c is the one that makes the most sense
Explanation:
Answer:
1500 milliradians
Explanation:
Data provided in the question:
1.5 radians
Now,
1 radians consists of 1000 milliradians
1 milli = 1000
thus for the 1.5 radians, we have
1.5 radians = 1.5 multiplied by 1000 milliradians
or
1.5 radians = 1500 milliradians
Hence, after the conversion
1.5 radians equals to the value 1500 milliradians
Answer:E = hc/? = 4.41 x 10-19 J
Energy absorbed by each atom :
E (atom) = 2.205 x 10-19 J
Now Bond Energy of each molecule (B) = 3.98 x J
So, for each atom 1.99 x 10-19 J
So now
KE of each atom = E(atom) - B (atom)
= 2.15 x 10-19 J
