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3 years ago

When energy is transferred from one part of a system to another, some of the

Physics

2 answers:

Bad White [126]3 years ago

7 0

Answer:

C. Friction between the moving parts of an airplane engine warms the parts as the engine burns fuel

A. An electric motor heats up as it powers a blender

Explanation:

just took the test

fenix001 [56]3 years ago

3 0

Answer:

its d

Explanation:

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A wheel in the shape of a flat, heavy, uniform, solid disk is initially at rest at the top of an inclined plane of height 2.00 m

olasank [31]

Answer:

Explanation:

If friction is neglected, the wheel cannot roll and can only slide frictionlessly and will have the same velocity at the bottom of the ramp as if it had been in free fall as it has converted the same amount of potential energy.

mgh = ½mv²

v = √(2gh) = √(2(9.81)(2.00)) = 6.26418... = 6.26 m/s

However if we do not ignore all friction and the wheel rolls without slipping down the slope, the potential energy becomes linear and rotational kinetic energy

mgh = ½mv² + ½Iω²

mgh = ½mv² + ½(½mR²)(v/R)²

2gh = v² + ½v²

2gh = 3v²/2

v = √(4gh/3) =√(4(9.81)(2.00)/3) = 5.11468... = 5.11 m/s

7 0

3 years ago

A vacuum gage connected to a chamber reads 39 kPa at a location where the atmospheric pressure is 92 kPa. Determine the absolute

Nata [24]

Answer: 53 kPa

Explanation:

Absolute pressure is a pressure value referred to absolute zero or vacuum. This value indicates the total pressure to which a body or system (the chamber in this situation) is subjected, considering the total pressure acting on it.

In this sense, the equation that will be useful in this case is:

$P_{atmospheric}= P_{absolute} + P_{vacuum}$ (1)

Where:

$P_{atmospheric}=92 kPa$ is the atmospheric pressure

$P_{vacuum}=39 kPa$ is the vacuum pressure

$P_{absolute}$ is the absolute pressure

Isolating $P_{absolute}$ from (1):

$P_{absolute}=P_{atmospheric} - P_{vacuum}$ (2)

$P_{absolute}=92 kPa - 39 kPa$ (3)

Finally:

$P_{absolute}=53 kPa=53(10)^{3} Pa$ This is the absolute pressure in the chamber

7 0

4 years ago

A massless spring with spring constant 16.4 N/m hangs vertically. A body of mass 0.193 kg is attached to its free end and then r

svet-max [94.6K]

Answer:

(A) 0.2306 m

(B) 1.467 Hz

(C) 0.1152 m

Explanation:

spring constant (K) = 16.4 N/m

mass (m) = 0.193 kg

acceleration due to gravity (g) = 9.8 m/s^{2}

(A) force = Kx, where x = extension

mg = Kx

0.193 x 9.8 = 16.4x

x = 0.1153 m

now the mass actually falls two times this value before it gets to its equilibrium position ( turning point ) and oscillates about this point

therefore

2x = 0.2306 m

(B) frequency (f) = \frac{1}{2π} x $\sqrt{\frac{k}{m}}$

frequency (f) = \frac{1}{2π} x $\sqrt{\frac{16.4}{0.193}}$

frequency = 1.467 Hz

(C) the amplitude is the maximum position of the mass from the equilibrium position, which is half the distance the mass falls below the initial length of the spring

= \frac{0.2306}{2} = 0.1152 m

8 0

3 years ago

Which is not a common property of ionic compounds

Naddik [55]

<h2>Answer:</h2>

Low melting points and electrical conductivity in solids are not common properties of ionic solids.

<h3>Explanation:</h3>

In ionic compounds the electrons involved in the bonding are tightly packed under the influence of electrostatic force of attraction. So the movement of these electrons is very difficult.

In the melting point the bond breaking between the atoms is involved. Hence in case of ionic compound there is a high amount of energy needed to break the ionic bonds.

Electrical conductivity involves the free movement of electrons which is impossible in ionic solids.

So low melting points and electrical conductivity in solids are not common properties of ionic solids.

6 0

3 years ago

a wave travels in a string at 58 m/s. a second string of 10% greater linear density has the same tension applied as in the first

ozzi

Answer:

The speed of wave in the second string is 55.3 m/s.

Explanation:

Given that,

Speed of wave in first string= 58 m/s

We need to calculate the wave speed