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baherus [9]
4 years ago
10

You need to repair a broken fence in your yard. The hole in your fence is around 3 meters in length and for whatever reason, the

store you go to has oddly specific width 20cm wood. Each plank of wood costs $16.20, how much will it cost to repair your fence?
Physics
1 answer:
Pachacha [2.7K]4 years ago
6 0

The correct answer is $243

Explanation:

The hole in the fence is 3 meters, this means it is necessary to buy wood that covers this distance. Now, each meter is equal to 100 centimeters, this means 3 meters is equivalent to 300 centimeters ( 100 cm in each meter x 3). Besides this, it is known each plank covers 20cm and costs $16.20. In this context, the next step is to find how many planks are needed. The process is shown below:

300 cm (total width) ÷ 20 cm (width of 1 plank) = 15 planks

This means 15 planks are needed. Finally, fin the total cost

15 planks x $16.20 (cost of 1 plan) = $243

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On a summer day, Thomas is standing in his driveway waiting for his mother. Energy from the Sun is making Thomas feel hot. This
Leno4ka [110]

Answer:

A. Energy streaming through space toward Thomas

Explanation:

its correct did it on a test

4 0
3 years ago
A white dwarf has a greater mass than either a red dwarf or a brown dwarf. Yet a white dwarf has a smaller radius than either a
Sauron [17]

Explanation:

Red dwarf and brown dwarf masses are less than a typical white dwarf mass measuring around 1.2 solar masses. But it's only a few kilometers of the radius. This is precisely because there is no force to overcome the contraction due to gravity. There is a constant  battle between the external force of fusion (who wants to expand the star) and inward pressure because of gravity (who wants to compact the star) of regular stars on the main sequence. There remains a balance between these two forces as long as the star remains on the celestial equator.

Red dwarfs are helped by the nuclear fusion force, but brown dwarfs were not large enough to cause the fusion of hydrogen, they are massive enough to generate sufficient energy in the core by fusing deuterium to sustain their volume.  However as soon as the star runs out of hydrogen to burn it weakens the force of the external fusion and gravity starts to compact the center of the star. The contraction heats up the core into more massive stars and helium fusion begins, rendering the star once again stable. However this helium fusion does not occur in stars with masses below 1.44Mo. Tightness persists for such stars until the star's gasses degenerate.

8 0
4 years ago
One method for determining the amount of corn in early Native American diets is the stable isotope ratio analysis (SIRA) techniq
Iteru [2.4K]

Answer:

0.0084575\ \text{T}

0.272\ \text{m}

2.2 cm easily observable

Explanation:

m_1 = Mass of 12 C = 1.99\times 10^{-26}\ \text{kg}

m_2 = Mass of 13 C = 2.16\times 10^{-26}\ \text{kg}

r_1 = Radius of 12 C = \dfrac{25}{2}=12.5\ \text{cm}

B = Magnetic field

v = Velocity of atom = 8.5 km/s

r_2 = Radius of 13 C

The force balance of the system is

qvB=\dfrac{m_1v^2}{r}\\\Rightarrow B=\dfrac{m_1v}{rq}\\\Rightarrow B=\dfrac{1.99\times 10^{-26}\times 8500}{12.5\times 10^{-2}\times 1.6\times 10^{-19}}\\\Rightarrow B=0.0084575\ \text{T}

The required magnetic field is 0.0084575\ \text{T}

Radius is given by

r=\dfrac{mv}{qB}

r\propto m

So

\dfrac{r_2}{r_1}=\dfrac{m_2}{m_1}\\\Rightarrow r_2=\dfrac{m_2}{m_1}r_1\\\Rightarrow r_2=\dfrac{2.16\times 10^{-26}}{1.99\times 10^{-26}}\times 12.5\times 10^{-2}\\\Rightarrow r_2=0.136\ \text{m}

The required diameter is 2\times 0.136=0.272\ \text{m}

Separation is given by

2(r_2-r_1)=2(0.136-0.125)=0.022\ \text{m}

The distance of separation is 2.2 cm which is easily observable.

5 0
3 years ago
When landing after a spectacular somersault, a 40.5 kg gymnast decelerates by pushing straight down on the mat. Calculate the fo
monitta

Answer:

F= = 3.18 * 10^3 N

Explanation:

information given:

m= 40.5 kg

a= seven times gravity so we have

a= 7 g

where

gravity = g  =9.8 m/s2

F= m*a

F= (40.5) * 7g

a = 7 g = (7) (9.8) = 68.6 m/s2

There are two forces acts on gymnsat

Where ,w is the weight of Gymnsat

F(net) = F - mg

F- mg = ma

F = mg+ma

so  

F=  m ( g + a)

F = (40.5) [9.8+ 68.6 ]

F = 3.18 * 10^3 N

4 0
4 years ago
The figure shows a positive charge placed in a uniform electric field. Is the force exerted on the +1 C charge directed up or do
raketka [301]

Answer:

the answer is down on e2020

Explanation:

3 0
3 years ago
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