Answer:
please in english......................................
Explanation:
At 4 m/s?
How do the two kinetic energies compare to one another? QUADRUPLES !
#3 What is the kinetic energy of a 2,000 kg bus that is moving at 30 m/s?
Potential energy
Answer: Velocity terminal = 0.093m/s
Explanation:
1. We start by evaluating the gap distance between the two cylinders as h = R(sleeve) - R(cylinder)
= (0.0604/2 - 0.06/2)m
= 2×10^-4
Surface are of the cylinder in the drop, which is required in order to evaluate the shearing stress can be expressed as A(cylinder) = π.d.L
= (π×0.06×0.4)m²
= 0.075m²
Since the force of the cylinder's weight is going to balance the shearing force on the walls, we can express the next equation and derive terminal velocity from it.
Shearing stress = u×V.terminal/h = 0.86×V/0.0002
= 4300Vterminal
Therefore, Fw = shearing stress × A
30N = 4300Vterminal × 0.075
V. terminal = 30/4300 m.s
V. terminal = 0.093m/s
The bowling ball will require more force to roll because it is more massive.
Answer:
I believe <u>kinetic / potential</u>
Explanation:
