D=event that chip selected is defective
d=event that chip selected is NOT defective
Four possible scenarios for the first two selections:
P(DDD)=15/100*14/99*13/98=13/4620
P(DdD)=15/100*85/99*14/98=17/924
P(dDD)=85/100*15/99*14/99=17/924
P(ddD)=85/100*84/99*15/98=17/154
Probability of third selection being defective is the sum of all cases,
P(XXD)=P(DDD)+P(DdD)+P(dDD)+P(ddD)
=3/20
X Y
————-
-2. -4
-1. -8
0. -12
1. -16
2. -20
Answer:
7x + 6 = 6x - 3
Step-by-step explanation:
2(x+3) + 5x = 3(2x-1)
Distribute
2x + 6 + 5x = 6x - 3
Combine like terms
7x + 6 = 6x - 3
hope this helps
